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Paraphin [41]
3 years ago
15

what is the equation in point-slope form of the line passing through (4, 0) and (2, 6)? y = 4x − 2 y = 2x − 4 y = −3(x − 4) y =

3(x 4)
Mathematics
1 answer:
Brilliant_brown [7]3 years ago
7 0
Equation in point slope form is given by y - y1 = m(x - x1); where m = (y2 - y1)/(x2 - x1).

y - 0 = (6 - 0)/(2 - 4) (x - 4)
y = 6/-2 (x - 4)
y = -3(x - 4)
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3 1/4 x 5/8? that is, 3 and 1/4 times 5/8
maw [93]

Answer:

first make mixed

13/4 x 5/8

just multiply the numerator with numerator and denominator with denominator

13x5=65

4x8=32

65/32 or 2 1/32

Step-by-step explanation:

6 0
3 years ago
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2. The following formula relates three quantities: Force (F), mass (m), and acceleration (a).
castortr0y [4]

Let

F--------> represent the force

m--------> represent the mass

a-------> represent the acceleration

we know that

The formula that relates three quantities: Force (F), mass (m), and acceleration (a) is equal to

F=ma

<u>Part a)</u> Solve this equation for a

F=ma

Divide both sides by the mass

a=\frac{F}{m}

therefore

<u>the answer part a) is equal to</u>

a=\frac{F}{m}

<u>Part b) </u>Let the force be 25 units and the mass be m = 10 units. What is the acceleration, a?

we know that

the formula of acceleration is equal to

a=\frac{F}{m}

in this problem

we have

F=25\\m=10

Substitute the values n the formula

a=\frac{25}{10}

a=2.5

therefore

<u>the answer part b( is equal to</u>

a=2.5

<u>Part c)</u> Let the force be F = 25 units and the acceleration be a = 5 units. What is the mass, m?

we know that

F=ma

Solve for m

Divide both sides by the acceleration

m=\frac{F}{a}

in this problem

we have

F=25\\a=5

Substitute the values n the formula

m=\frac{25}{5}

m=5

therefore

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m=5

5 0
3 years ago
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How do you graph a linear function to a line graph
anygoal [31]

Answer:

use point slope form

y=mx+b

8 0
3 years ago
For what value of x is (2x^2+8x)/(x+4)(x^2-9) undefined?
irakobra [83]

Answer:

The value at x =3 is undefined for the given expression

Step-by-step explanation:

Given expression is \frac{2x^2+8x}{(x+4)(x^2-9)}

To find for what value of x is undefined in the given expression :

\frac{2x^2+8x}{(x+4)(x^2-9)}=\frac{2x(x+4)}{(x+4)(x^2-9)}

=\frac{2x}{x^2-9}

\frac{2x^2+8x}{(x+4)(x^2-9)}=\frac{2x}{x^2-9}

If we put x=3 in the above expression we get

\frac{2x}{x^2-9)}=\frac{2(3)}{3^2-9}

=\frac{6}{9-9}

=\frac{6}{0}

Therefore \frac{2x^2+8x}{(x+4)(x^2-9)}=\frac{6}{0}

The value at x =3 is undefined for the given expression

7 0
3 years ago
Mason bought a tablecloth that measured 8 feet by 4 feet.
Y_Kistochka [10]
32feet because 8×4=32
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