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mash [69]
3 years ago
12

Triangle CDE with vertices C(-2,-2) D(1,-4) and E(-3,-4) has a dilation with scale factor of 4 centered (-1,-3) and reflected ac

ross the line y=-x
Mathematics
1 answer:
balu736 [363]3 years ago
7 0

Answer:Mr. Sullivan places tiles numbered 1 through 18 in a bag and assigns a number to represent each of the 18 students in his class. Students will present their final reports in the order that their assigned tiles are drawn from the bag. Is Mr. Sullivan being fair? Use the drop-down menus to explain your answer.

Step-by-step explanation:

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Just 4 people per year would overflow the landfill, how would it survive 6480 people?

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mafiozo [28]

group1 a = 0.25

group1 b = 0.75


group2 a = 0.44

group2 b = 0.56

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3 years ago
Lesson: 1.08Given this function: f(x) = 4 cos(TTX) + 1Find the following and be sure to show work for period, maximum, and minim
Ber [7]

The given function is

f(x)=4\cos \text{(}\pi x)+1

The general form of the cosine function is

y=a\cos (bx+c)+d

a is the amplitude

2pi/b is the period

c is the phase shift

d is the vertical shift

By comparing the two functions

a = 4

b = pi

c = 0

d = 1

Then its period is

\begin{gathered} \text{Period}=\frac{2\pi}{\pi} \\ \text{Period}=2 \end{gathered}

The equation of the midline is

y_{ml}=\frac{y_{\max }+y_{\min }}{2}

Since the maximum is at the greatest value of cos, which is 1, then

\begin{gathered} y_{\max }=4(1)+1 \\ y_{\max }=5 \end{gathered}

Since the minimum is at the smallest value of cos, which is -1, then

\begin{gathered} y_{\min }=4(-1)+1 \\ y_{\min }=-4+1 \\ y_{\min }=-3 \end{gathered}

Then substitute them in the equation of the midline

\begin{gathered} y_{ml}=\frac{5+(-3)}{2} \\ y_{ml}=\frac{2}{2} \\ y_{ml}=1 \end{gathered}

The answers are:

Period = 2

Equation of the midline is y = 1

Maximum = 5

Minimum = -3

3 0
1 year ago
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