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storchak [24]
3 years ago
15

How do you balance the equation Hydrogen plus Oxygen yield water?

Chemistry
1 answer:
Andre45 [30]3 years ago
5 0
Hey there! Hello!

Not sure if you still need the answer to this question, but I'd love to help out if you do. 

So, the way to balance this equation is pretty simple. First, you need to keep in mind that molecules of hydrogen and oxygen do not come in single molecules, but in bonded pairs, represented by H2 and O2. 

H2+O2=H2O

But, that's incorrect. The combination of 2 hydrogen molecules with 1 oxygen molecule yields water, but that leaves one oxygen molecule leftover. When broken down, this is how many of each molecule is on each side of the previously stated equation:

Left:
H: 2
O: 2

Right:
H: 2
O: 1

So we have to multiply H2O on the right side by 2 in order to get this:

H2+O2=2(H2O)

Left: 
H: 2
O: 2

Right: 
H: 4
O: 2

The last step is to multiply H2 on the left by two to make it match up with the right side, balancing the equation:

2(H2)+O2=2(H2O)

Left: 
H: 4
O: 2

Right: 
H: 4
O: 2

That makes our equation balanced! I hope this helped you out, feel free to ask any additional questions if you need further clarification. :-)
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A first order reaction has a rate constant of 0. 543 at 25°C. Given that the activation energy is 75. 9 kj/mol. Calculate the ra
Rasek [7]

The rate constant of first order reaction at 32. 3 °C is 0.343 /s must be less the 0. 543 at 25°C.

First-order reactions are very commonplace. we have already encountered  examples of first-order reactions: the hydrolysis of aspirin and the reaction of t-butyl bromide with water to present t-butanol. every other reaction that famous obvious first-order kinetics is the hydrolysis of the anticancer drug cisplatin.

The value of ok suggests the equilibrium ratio of products to reactants. In an equilibrium combination both reactants and merchandise co-exist. big ok > 1 merchandise are k = 1 neither reactants nor products are desired.

Rate constant K₁  = 0. 543 /s

T₁  = 25°C

Activation energy Eₐ =  75. 9 k j/mol.

T₂ = 32. 3 °C.

K₂ =?

formula;

log K₂/K₁=  Eₐ /2.303 R [1/T₁ - 1/T₂]

putting the value in the equation  

K₂ = 0.343 /s

Hence, The rate constant of first order reaction at 32. 3 °C is 0.343 /s

The specific rate steady is the proportionality consistent touching on the fee of the reaction to the concentrations of reactants. The fee law and the specific charge consistent for any chemical reaction should be determined experimentally. The cost of the charge steady is temperature established.

Learn more about activation energy here:- brainly.com/question/26724488

#SPJ4

4 0
1 year ago
How long is a red blood cell
Lera25 [3.4K]
I suspect this question should read "How long does a red blood cell live." A red blood cell lives for between 100 and 120 days. It takes 7 days for a new red blood cell to develop from stem cells. Stem cells are similar to base cells. They can also be seen as a general template from which specialized cells are made. Stem cells can be taken from a newborn baby's umbilical chord or extracted from an adult blood donor's blood.This 
7 0
3 years ago
0.005 molar Ca(OH)2 solution is used in the titration.calculate the pH oh solution
Rus_ich [418]

Ca(OH)₂: strong base

pOH = a . M

a = valence ( amount of OH⁻)

M = concentration

Ca(OH)₂ ⇒ Ca²⁺ + 2OH⁻ (2 valence)

so:

pOH = 2 x 0.005

pOH = 0.01

pH = 14 - 0.01 = 13.99

6 0
2 years ago
Calculate the total pressure in a mixture of 8 g of dioxygen and 4 g of dihydrogen confined in a vessel of 1 dm8 at 27 ∘C. (R =
maxonik [38]

Answer:

Total pressure =  56.77 bar

Explanation:

Given data:

Mass of dioxygen = 8 g

Mass of dihydrogen = 4 g

Volume of vessel = 1 dm³

Temperature = 27°C (27+273 = 300 K)

R = 0.083 bar.dm³ / mol.K

Total pressure = ?

Solution:

Number of moles of dioxygen:

Number of moles = mass/molar mass

Number of moles = 8 g/ 32 g/mol

Number of moles = 0.25 mol

Pressure of dioxygen:

PV = nRT

P = nRT/V

P = 0.25 mol × 0.083 bar.dm³ / mol.K × 300 K / 1 dm³

P = 6.97 bar.dm³  /1 dm³

P = 6.97 bar

Number of moles of dihydrogen:

Number of moles = mass/molar mass

Number of moles = 4 g/ 2 g/mol

Number of moles = 2 mol

Pressure of dihydrogen:

PV = nRT

P = nRT/V

P = 2 mol × 0.083 bar.dm³ / mol.K × 300 K / 1 dm³

P = 49.8 bar.dm³  /1 dm³

P = 49.8 bar

Total pressure of mixture in a vessel:

Total pressure = P (O₂) + P(H₂)

Total pressure =  6.97 bar + 49.8 bar

Total pressure =  56.77 bar

7 0
3 years ago
What is the percentage composition of CF4
adoni [48]
The percentage composition of CF4 is %C = 13.64% and %F = 86.36% 

The solution are as follows:
Molar mass of CF4 = 88 
<span>molar mass of C = 12 </span>
<span>molar mass of F = 4x19 = 76 </span>

<span>% C = 12/88 x 100 = 13.64% </span>
<span>% F = 76/88 x 100 = 86.36%</span>
8 0
3 years ago
Read 2 more answers
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