Question

How many moles are present in 10.5 grams of NaCl?

Answer 1

Answer : The number of moles present in 10.5 grams of NaCl are, 0.179 moles.

Solution : Given,

Mass of NaCl = 10.5 g

Molar mass NaCl = 58.5 g/mole

Formula used :

$\text{Moles of NaCl}=\frac{\text{Mass of NaCl}}{\text{Molar mass of NaCl}}$

Now put all the given values in this formula, we get the moles of NaCl

$\text{Moles of NaCl}=\frac{10.5g}{58.5g/mole}=0.179moles$

Therefore, the number of moles present in 10.5 grams of NaCl are, 0.179 moles.

Answer 2

Mr of NaCl = 58.5


Mole = mass÷ Mr..

Mole od NaCl = 10.5 ÷ 58.5 = 0.179