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3 years ago

Calculate the pH of 100.0 mL of a 0.150M aqueous solution of HNO3

1 answer:

7 0

PH scale is used to determine how acidic, neutral or basic a solution is.
pH can be calculated using the following equation
pH = -log[H⁺]
HNO₃ is a strong acid therefore completely dissociates into its ions as follows
HNO₃ --> H⁺ + NO₃⁻
1 mol of HNO₃ dissociates to produce 1 mol of H⁺ ions
Therefore [HNO₃] = [H⁺]
[H⁺] = 0.150 M
since concentration has been given, its not necessary to consider the volume as concentration is constant throughout the whole solution
pH = -log(0.150 M)
pH = 0.82
the pH of solution is 0.82

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A method used by the U.S. Environmental Protection Agency (EPA) for determining the concentration of ozone in air is to pass the

baherus [9]

Answer: 1. $9.08\times 10^{-6}$ moles

2. 90 mg

Explanation:

$O_3(g)+2NaI(aq)+H_2O(l) \rightarrow O_2(g)+I_2(s)+2NaOH(aq)$

According to stoichiometry:

1 mole of ozone is removed by 2 moles of sodium iodide.

Thus $4.54 \times 10^{-6}$ moles of ozone is removed by = $\frac{2}{1}\times 4.54 \times 10^{-6}=9.08\times 10^{-6}$ moles of sodium iodide.

Thus $9.08\times 10^{-6}$ moles of sodium iodide are needed to remove $4.54\times 10^{-6}$ moles of $O_3$

2. $\text{Number of moles of ozone}=\frac{0.01331g}{48g/mol}=0.0003moles$

According to stoichiometry:

1 mole of ozone is removed by 2 moles of sodium iodide.

Thus 0.0003 moles of ozone is removed by = $\frac{2}{1}\times 0.0003=0.0006$ moles of sodium iodide.

Mass of sodium iodide= $moles\times {\text {molar mass}}=0.0006\times 150g/mol=0.09g=90mg$ (1g=1000mg)

Thus 90 mg of sodium iodide are needed to remove 13.31 mg of $O_3$ .

3 0

3 years ago

I typed a question. It said give points. I selected. Someone answered notification came. But where do I see they persons answer?

Ksivusya [100]

Answer:

212.304 grams

Explanation:

similar to your other question, use the same formula

q=mCpΔT

23617=m(4.182)(46.6-20)

23617=111.2412m

m=212.304g

6 0

2 years ago

Charcoal found under a stone at Stonehenge, England, has a carbon-14 activity that is 0.60 that of new wood. How old is the char

kenny6666 [7]

Charcoal with a carbon-14 activity of 0.60 compared to new wood has less than 5,730 years.

<h3>What is a radioactive isotope?</h3>

A radioactive isotope is an element in nature that emit radioactivity in a given period of time (e.g., the half-life for C14 is equal to 5,730 years).

Radioactive dating is a technique to measure the age of an element by measuring its radioactive activity.

In conclusion, charcoal with a carbon-14 activity of 0.60 compared to new wood has less than 5,730 yr.

Learn more about radioactive dating here:

brainly.com/question/8831242

#SPJ1

5 0

1 year ago

Write a general word equation for a neutralization reaction.

xenn [34]

Hydrochloric acid + Sodium hydroxide =Sodium chloride +water

8 0

3 years ago

Arrange the compounds in order of decreasing magnitude of lattice energy:

Alik [6]

Answer:

The correct answer is CaO > LiBr > KI.

Explanation:

Lattice energy is directly proportional to the charge and is inversely proportional to the size. The compound LiBr comprises Li+ and Br- ions, KI comprises K+ and I- ions, and CaO comprise Ca²⁺ and O²⁻ ions.

With the increase in the charge, there will be an increase in lattice energy. In the given case, the lattice energy of CaO will be the highest due to the presence of +2 and -2 ions. K⁺ ions are larger than Li⁺ ion, and I⁻ ions are larger than Br⁻ ion.

The distance between Li⁺ and Br⁻ ions in LiBr is less in comparison to the distance between K⁺ and I⁻ ions in KI. As a consequence, the lattice energy of LiBr is greater than KI. Therefore, CaO exhibits the largest lattice energy, while KI the smallest.

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3 years ago