A 20.0 mL sample of a NaCl solution has a mass of 21.040g. After the solution is evaporated to dryness, the dry salt residue has

Question

yanalaym [24]

4 years ago

11

A 20.0 mL sample of a NaCl solution has a mass of 21.040g. After the solution is evaporated to dryness, the dry salt residue has

a mass of 4.348g. Calculate the following concentrations for the NaCl solution. (Molarity)

Chemistry

1 answer:

Vilka [71] · Answer 1 · 2021-11-12T13:03:56+03:00

Vilka [71]4 years ago

7 0

Mass NaCl = 4.348
Mass solution = 21.040 - 4.348 = 16.692
mass/mass % =
4.348/16.692
= 26%
mass/vol % =
21.7%
Molecular mass of NaCl = 58.5
Moles of NaCl = 0.074
Volume of solution = 0.02 L
Molarity = 3.7 mol/Liter