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2 years ago

Express the solution of, x^3 + 2x^2 < x + 2, using interval notation.

Mathematics

1 answer:

Rudiy272 years ago

6 0

x³ + 2x² - x - 2 < 0

x³ - x + 2x² - 2 < 0

x(x² - 1) - 2(x² - 1) < 0

(x - 2)(x² - 1) < 0

(x - 2)(x - 1)(x + 1) < 0

by chacking we get the solution

x ∈ (-∞,-1) ∪ (-1,1)

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Answer:

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Step-by-step explanation:

Geometric sequence

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Given:

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Therefore:

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To find the sum of the first 20 terms, substitute the found values of a and r, together with n = 20, into the formula:

$\implies S_{20}=\dfrac{4\left(1-\left(\frac{8}{9}\right)^{20}\right)}{1-\left(\frac{8}{9}\right)}$

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$\implies S_{20}=32.59\:\: \sf (nearest\:hundredth)$

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1 year ago

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navik [9.2K]

Answer:

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Step-by-step explanation:

The given function is

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This means that wherever we see t, we put 2

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$F(2) = \frac{1}{32}$

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Step-by-step explanation:

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