1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Dvinal [7]
3 years ago
8

The cross section of a parabolic reflector has a vertical axis of symmetry with its vertex at (0,0) . The focus of the reflector

is 6 feet above the vertex. The reflector extends 4.5 feet to either side of the vertex. What is the depth of the reflector? Round your answer to the nearest hundredth.

Mathematics
1 answer:
Paha777 [63]3 years ago
4 0

Answer:

The depth of the reflector is 0.84 feet

Step-by-step explanation:

<em>(See the figure below)</em>

The equation of a parabola centered at the origin with an axis of symmetry on y-axis is:

x^{2}=4py (1)

With p the distance from the origin to the focus using p=6, the equation (1) of the parabola becomes:

x^{2}=4(6)y=24y (2)

Note that the point B is on the parabola, so this point should satisfy the parabola equation (2) that allow us to use the value x=4.5 to find the y value associated to it, that it is the depth (h) of the reflector:

(4.5)^{2}=24y, solving for y

y=\frac{(4.5)^{2}}{24}\approx0.84\,ft

You might be interested in
Find the value of x pls help
bogdanovich [222]

Answer: 90 degrees

Step-by-step explanation:

It is a right angle which means it is 90 degrees. Plz mark me brainliest

5 0
2 years ago
The density of aluminum is 2.375 grams per cubic centimeter. Find the volume of a portion of a sheet of aluminum that has a mass
Rufina [12.5K]
This is the concept of density, volume and mass of different materials; To calculate for the volume of an aluminium material with density of 2.375 grams per cubic centimeter and a mass of 0.78 Kilogram we proceed as follows;
Density=mass/volumemaking volume the subject we get;volume=mass/densitythus;mass=0.78 kg= 780 gdensity=2.375 g/cm^3Hence,volume=780/2.375=328.421 cm^3

4 0
3 years ago
Can someone please help me ASAP
Vaselesa [24]

Answer:

B.

Step-by-step explanation:

Hope this helps!

6 0
3 years ago
Geometry help needed!
lilavasa [31]

Answer:

13.76

Step-by-step explanation:

Area of the whole

The area of the whole = s^2 (the firgure is a square

s = 8

Area of the whole = 8^2 = 64

Area of the unshaded part

The 2 half circles = 1 whole circle

The radius of the 1/2 circle = 4 (eight has been cut in half)

Area of two half circles = 2* (pi r^2/2)

Area of two half circles = 2 * (pi 4^2/2)

area of two half circles =  16*pi

Area of the shaded area

Area of the shaded area = area of the whole - area of the unshaded area

Area of the shaded area = 64 - 16*pi

Area of the shaded area = 64 - 3.14*16 = 13.76

4 0
3 years ago
HELP ASAP What is the slope-intercept equation of a line with slope -5 and y-intercept 3/2?
8090 [49]

The Answer is:

C. x=-5+3/2

7 0
3 years ago
Read 2 more answers
Other questions:
  • Sam went to 35 basketball games this year. He went to 29 games last year. And will go to 17 this year. How many basketball games
    11·2 answers
  • The tree in Juan's backyard is 7.7 m high. How high is it in centimeters?
    10·2 answers
  • Find the slope and the y-intercept of the line. 6x + 3y = -3 Write your answers in simplest form​
    5·1 answer
  • What are the answers ?
    13·2 answers
  • PLEASE HELP I NEED TO DO THIS BUT I DON’T KNOW HOW
    14·1 answer
  • Write the slope intercept form of the equation of each line.
    7·1 answer
  • PLEASE HELP<br> 10 points<br> will mark brainliest!
    10·1 answer
  • Jasmine swims 12 laps every afternoon, Monday through Friday. How many laps does she swim in one week?
    8·2 answers
  • For each fraction, decimal, or percent, write the equivalent number from the list below. 0.68, 19/50, 9/20, 80%, 0.54. A. 38% __
    11·1 answer
  • What is the value of x when the richter scale rating scale is 8.4?
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!