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Allushta [10]
3 years ago
12

What are the four major categories of securities? How are they evaluated?

Mathematics
1 answer:
Xelga [282]3 years ago
5 0

Answer:

Cash, Bonds, Stocks and Mutual funds

Step-by-step explanation:

The four major categories of securities are:  

  1. Cash
  2. Bonds
  3. Stocks
  4. Mutual funds

These 4  major categories are evaluated as given below:  

  • Cash: Cash is your normal money. You can use it to buy your everyday goods and services or invest in cash in various asset classes.
  • Bonds: Bond is debt instrument and bonds are the agreement of debt. and bonds carry coupon rate that is (interest equivalent), tenure and final capital repayment
  • Stocks: Ownership of stock in a company. A group (or a single) share of any company is called stock. Stock means you have some stake in the company.
  • Mutual Funds: A mutual fund is an asset basket that can hold cash, bonds, stocks, real estate, and so on. The type and structure of mutual funds will vary depending on the client's choice of the fund manager and the category of the category
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Hi can someone pls help me, I’m confused
gregori [183]

Answer:

(E) 72 w^2 is the answer

Step-by-step explanation:

outer square area is 81 w^2

inner square area is 9 w^2

subtracting outer - inner we can get the shaded area

so 81 -9= 72w^2

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3 years ago
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lapo4ka [179]
2.485 is round to 450 and 450 divide by 15 equals 30. 485 divide by 15 32 r 5
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3 years ago
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valentinak56 [21]

Step-by-step explanation:

\huge \: 2 \sqrt{x} .4  {x}^{ -  \frac{5}{2} } \\  \\   \huge \: = 2.4 {x}^{ \frac{1}{2} }  . {x}^{ -  \frac{5}{2} } \\  \\ \huge \:   = 8 {x}^{ \frac{1}{2}  -  \frac{5}{2} }  \\  \\   \huge \: = 8 {x}^{ \frac{1 - 5}{2} }  \\  \\ \huge \:   = 8 {x}^{ -  \frac{4}{2} }  \\  \\ \huge \:   = 8. {x}^{ - 2}  \\

4 0
3 years ago
If g(x)= square root of 3-5x, find the domain of g'(x).
BaLLatris [955]

Answer:

domain: x>3/5

Step-by-step explanation:

First we need to derive our function g(x) to get a new function g'(x)

To do this we will have to apply chain rule because we have an inner and outer functions.

Our G(x) = square root(3-5x)

Chain rule formula states that: d/dx(g(f(x)) = g'(f(x))f'(x)

where d/dx(g(f(x)) = g'(x)

g(x) is the outer function which is x^1/2

f(x) is our inner function which is 3-5x

therefore f'(x)= 1/2x^(-1/2) and f'(x) = -5

g'(f(x)) = -1/2(3-5x)^(-1/2)

Applying chain rule then g'(x) = 1/2 (3-5x)^(-/1/2)*(-5)

But the domain is the values of x where the function g'(x) is not defined

In this case it will be 3-5x > 0, because 3-5x is a denominator and anything divide by zero is infinity/undefined

which gives us x >3/5

5 0
3 years ago
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What is true of a sequence of transformations that rotates an image and then translates it in order to map it onto another image
joja [24]

The true statement about the sequence of transformations is it includes exactly two rigid transformations.

<h3>How to determine the true statement?</h3>

The transformation statement is given as:

a sequence of transformations that rotates an image and then translates it in order to map it onto another image

This can be split as follows:

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Translation and rotation are rigid transformations

This means that the size and the angle of the shape that is transformed will remain the same

Hence, the true statement about the sequence of transformations is it includes exactly two rigid transformations.

Read more about transformation at

brainly.com/question/4289712

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