3 years ago

How can you tell from the scale factor whether the original figure was enlarged or reduced?

Mathematics

2 answers:

Stels [109]3 years ago

8 0

If the scale factor is less then 1, it was reduced.

If the scale factor is more than 1, it was enlarged.

If it is equal to 1, it is the same.

Hope this helps!

fredd [130]3 years ago

7 0

If scale factor 1 it’s reduced

You might be interested in

Rationalise the denominator and simplify

Alexandra [31]

5 0

3 years ago

I need the answer asap 20 points

Mekhanik [1.2K]

Answer:

,,,,,,,,,,,,,,, ,,,,,,,,

5 0

3 years ago

Verify that the roots of 5x²- 6x -2 = 0 are <img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%20%2B%20%5Csqrt%7B19%7D%20%7D%7B5%7D%2

Mice21 [21]

Answer:

Proof below.

Step-by-step explanation:

Quadratic Formula

$x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0$

Given quadratic equation:

$5x^2-6x-2=0$

Define the variables:

a = 5
b = -6
c = -2

Substitute the defined variables into the quadratic formula and solve for x:

$\implies x=\dfrac{-(-6) \pm \sqrt{(-6)^2-4(5)(-2)}}{2(5)}$

$\implies x=\dfrac{6 \pm \sqrt{36+40}}{10}$

$\implies x=\dfrac{6 \pm \sqrt{76}}{10}$

$\implies x=\dfrac{6 \pm \sqrt{4 \cdot 19}}{10}$

$\implies x=\dfrac{6 \pm \sqrt{4}\sqrt{19}}{10}$

$\implies x=\dfrac{6 \pm2\sqrt{19}}{10}$

$\implies x=\dfrac{3 \pm \sqrt{19}}{5}$

Therefore, the exact solutions to the given quadratic equation are:

$x=\dfrac{3 + \sqrt{19}}{5} \:\textsf{ and }\:x=\dfrac{3 - \sqrt{19}}{5}$

Learn more about the quadratic formula here:

brainly.com/question/28105589

brainly.com/question/27953354

3 0

1 year ago

Read 2 more answers

Which expressions are equivalent?

vova2212 [387]

A) 3(a - b) = 3*a +3*-b = 3a - 3b EQUAL

b) 2a(2 + b) = 4a + 2ab NOT EQUAL

3 0

3 years ago

Read 2 more answers

A door opening is 2 meters high. If there is a 39 centimeter gap between the top of Casey's head and the top of the door opening

sammy [17]

You should find that Casey is 161 cm tall.

8 0

3 years ago