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3 years ago

Which fraction is between 3/20 and 7/10

Mathematics

1 answer:

slavikrds [6]3 years ago

8 0

5/15 depending on what the answers are

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If two angles are both obtuse, the two angles are equal

yan [13]

If two angles are equal, then the two angles are obtuse.

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3 years ago

I need help ASAP 30 points+brainleist

yulyashka [42]

Answer:

A) 40 feet.

B) 7 inches.

Step-by-step explanation:

A) To acquire 8 inches, multiply the corresponding scale factor by 8:

1 inch equals 5 feet; 8 inches equals 40 feet

The genuine house stands 40 feet tall.

B) You can write the percentage if you want...

dwg / (35 feet) = 1 in / (5 ft)

When you multiply by 35 feet, you get...

7 in dwg = (1 in)(35 ft)/(5 ft)

In the scale drawing, the home measures 7 inches in length.

5 0

2 years ago

Read 2 more answers

TRUE or FALSE

kupik [55]

Answer:

True

Step-by-step explanation:

~Is SAA side-angle-angle

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2 years ago

Number of Boxes Cost 18 $7.38 27 $15.39 30 $13.50 36 $18.36 40 $18.80 An office is restocking office supplies. The table shows t

malfutka [58]

Answer:

18 clips for $7.38 is the best value deal.

Step-by-step explanation:

An office is restocking office supplies. The table below shows the cost for the number of boxes of paperclips. We need to find what is the best value is.

To find the best value for money we can check the price of each paperclip.

To check the price of each paper clip we can use the following formula:

$\text{Price of each paper clip} =\frac{\text { price of the box }} {{\text {number of clips in the box }}}$

Now we can calculate the best value deal as follows:

$\text{Price of each clip is box 1}=\frac{7.38}{18}=0.41$$

$\text{Price of each clip is box 2}=\frac{15.39}{27}=0.57$$

$\text{Price of each clip is box 3}=\frac{13.50}{30}=0.45$$

$\text{Price of each clip is box 4}=\frac{18.36}{36}=0.51$$

$\text{Price of each clip is box 5}=\frac{18.80}{40}=0.47$$

So, from looking at the prices of each paperclip we can conclude that the 18 clips for $7.38 is the best value deal.

8 0

3 years ago

There are currently 17 frogs in a (large) pond. The frog population grows exponentially, tripling every 6 days. How long will it

Tema [17]

Answer:

t=11,11 days

Step-by-step explanation:

F=frogs poblation, t=time, be the variables dF/dt = KF, dF/F=Kdt, integrating $\int\limits^ {} \, dF/F =K\int\limits^ {} \, dt$ ⇒ LnF=Kt+c, $F=ce^{Kt}$ ; Knowing t=0, F=17 and t=6 F=51 (tripling every 6 days (17*3)), $F=ce^{K0} = F=c=17; F=17e^{6K} =51$ ⇒ $e^{6K} =51/17; K6=ln\frac{51}{17} ; K=ln\frac{51}{17}/6=0.183$ , so $F=17e^{0,183t}$ , now if F=130, t=? we have:

$130=17e^{0.183t} =e^{0.183t} =130/17; 0.183t=ln(130/17); t=ln(130/17)/0.183 = 11,11$

8 0

3 years ago