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Sindrei [870]
3 years ago
9

I need to know what is 2x+4

Mathematics
2 answers:
dsp733 years ago
8 0

it’s 6 hope this helps

morpeh [17]3 years ago
3 0

Answer:

6

Step-by-step explanation:

hope this helps

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Is this a real person ​
Leto [7]

Answer:

who

Step-by-step explanation:

3 0
3 years ago
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Lashonda purchased a prepaid phone card for $20. Long distance calls cost 8 cents a minute using this card. Lashonda used her ca
Gre4nikov [31]

We know that

• Lashonda purchased a prepaid phone card for $20.

,

• Long-distance calls cost 8 cents a minute.

,

• The remaining credit on her card is $17.12.

This problem can be expressed as

20-0.08x=17.12

Where <em>x</em> is the number of minutes.

We solve the equation for <em>x</em>

\begin{gathered} -0.08x=17.12-20 \\ -0.08x=-2.88 \end{gathered}

Then, we divide by -0.08 the equation

\begin{gathered} \frac{-0.08x}{-0.08}=\frac{-2.88}{-0.08} \\ x=36 \end{gathered}<h2>Therefore, Lashonda's call last 36 minutes.</h2>

8 0
1 year ago
Translate into an algebraic expressions: 120 is increased by d% and increased by 25% . What is the result ?
anastassius [24]

Answer:

The result is 150 + 1.5d

Step-by-step explanation:

We want to translate the wordings into algebraic expression.

Firstly, we increase 120 by d%

d% = d/100

So increasing 120 by d % means;

120 + (d/100 * 120)

= 120 + 1.2d

Then increase this by 25%

= (120 + 1.2d) + 25/100(120 + 1.2d)

= 120 + 1.2d + (120+1.2d)/4

= 120 + 1.2d + 30 + 0.3d

= 120 + 30 + 1.2d + 0.3d

= 150 + 1.5d

3 0
3 years ago
There are 1,657 souvenir paperweights that need to be packed in boxes. Each box will hold 17
blondinia [14]

Answer:

Therefore we can say that 98 boxes will be needed to hold all the paperweights.

Step-by-step explanation:

i) there are 1657 souvenir paperweights that need to be packed in boxes.

ii) each box will hold 17 paperweights

iii) therefore the number of boxes that will be needed are

   = \dfrac{total\hspace{0.15cm} number\hspace{0.15cm} souvenir\hspace{0.15cm} paperweights}{number\hspace{0.15cm} of\hspace{0.15cm} paperweights\hspace{0.15cm} per\hspace{0.15cm} box}  = \dfrac{1657}{17} = 97.471

iv) Therefore we can say that 98 boxes will be needed to hold all the paperweights.

4 0
3 years ago
What is -11/6 + m = -2/9
Helen [10]

Answer:

29/18

Step-by-step explanation:

-11/6 + m = -2/9

Add 11/6 to both sides.

+11/6  -11/6 + m = -2/9  +11/6

m=29/18

7 0
3 years ago
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