Answer:
refer to the above attachment
Answer:
Example of matrices such hat 
Step-by-step explanation:
We have two give example of 2×2 matrices such that AB = AC BUT B ≠ C.
Example:
![A =\left[\begin{array}{ccc}1&0\\0&0\end{array}\right]\\\\B = \left[\begin{array}{ccc}1&1\\1&2\end{array}\right], C = \left[\begin{array}{ccc}1&1\\1&3\end{array}\right]](https://tex.z-dn.net/?f=A%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%5C%5C0%260%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5CB%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%261%5C%5C1%262%5Cend%7Barray%7D%5Cright%5D%2C%20C%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%261%5C%5C1%263%5Cend%7Barray%7D%5Cright%5D)
Solving:
![AB = \left[\begin{array}{ccc}1+0&1+0\\0+0&0+0\end{array}\right] = \left[\begin{array}{ccc}1&1\\0&0\end{array}\right]](https://tex.z-dn.net/?f=AB%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%2B0%261%2B0%5C%5C0%2B0%260%2B0%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%261%5C%5C0%260%5Cend%7Barray%7D%5Cright%5D)
![AC = \left[\begin{array}{ccc}1+0&1+0\\0+0&0+0\end{array}\right] = \left[\begin{array}{ccc}1&1\\0&0\end{array}\right]](https://tex.z-dn.net/?f=AC%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%2B0%261%2B0%5C%5C0%2B0%260%2B0%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%261%5C%5C0%260%5Cend%7Barray%7D%5Cright%5D)
Hence,
Answer:
(-4,-8)
X is the first number, y is the second number.
Step-by-step explanation:
39° or B that should be it
Surface Area is the area of each face added together. For this question lets find the area of one triangle first.
Area of a triangle is base*hight/2, so 6*7/2=21. That was the area of one triangle. We have 4 traingle so we multiply that by for. 21*4=84.
Now, lets find the area of the squre. area of square is side*side or side^2.
So we multiply 6*6=36. that is the area of the square.
To find the surface area, we must add Area of Triangles+Area of Square.
so, 84+36=120
So the surface area is 120
