I think the answer could be C
Answer:
1.4
Step-by-step explanation:
9.5+0.9t
=9.5+0.9(-9)
=9.5+-8.1
=1.4
Michael took the return trip at a velocity 33.75 miles per hour.
<h3>How fast did Michael drive in his return trip?</h3>
Let suppose that Michael drove in <em>straight line</em> road and at <em>constant</em> velocity. Therefore, the speed of the vehicle (v), in miles per hour, can be defined as distance traveled by the vehicle (d), in miles, divided by travel time (t), in hours.
First trip
45 = s / 3 (1)
Second trip
v = s / 4 (2)
By (1) and (2):
45 · 3 = 4 · v
v = 33.75 mi / h
Michael took the return trip at a velocity 33.75 miles per hour.
To learn more on velocities: brainly.com/question/18084516
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This is a conversion problem. We know that 1 mile is 5280 feet, right? Since Ellie lives 2 miles, and two is double of 1, we just take 5280 and multiply that by two (or add it twice) to find how many feet is between Ellie's house and school. 5280 x 2 = 10560 (you get the same answer if you add 5280 twice). Therefore, 10560 feet lies between Ellie's house and school.
