<span> I am assuming you want to prove:
csc(x)/[1 - cos(x)] = [1 + cos(x)]/sin^3(x).
</span>
<span>If we multiply the LHS by [1 + cos(x)]/[1 + cos(x)], we get:
LHS = csc(x)/[1 - cos(x)]
= {csc(x)[1 + cos(x)]/{[1 + cos(x)][1 - cos(x)]}
= {csc(x)[1 + cos(x)]}/[1 - cos^2(x)], via difference of squares
= {csc(x)[1 + cos(x)]}/sin^2(x), since sin^2(x) = 1 - cos^2(x).
</span>
<span>Then, since csc(x) = 1/sin(x):
LHS = {csc(x)[1 + cos(x)]}/sin^2(x)
= {[1 + cos(x)]/sin(x)}/sin^2(x)
= [1 + cos(x)]/sin^3(x)
= RHS.
</span>
<span>I hope this helps! </span>
Answer:whats the question
Explanation:(pls dont report me as soon as u tell me the question i will edit my answer and answer correctly)
Answer:
y = -2x + 5
Х-y= 9
2x + y = 4
y = 5
lmk if incorrect, please give brainliest
Answer:
145%. The left one is 100% and then the right is the 45%.
Answer:
<h2>C.</h2>
Step-by-step explanation:
<, > - open circle
≤, ≥ - solid circle
<, ≤ - draw to the left
>, ≥ - draw to the right
