Answer:
1 and 2 go in the 2nd area and 3 gos to the 1st and 4th gos to the last one
Step-by-step explanation:
hope this helped!
P.S. can i pls have brainlyist am trying to lv up thx! ;D
Answer:
%82.5
Step-by-step explanation:
- The final exam of a particular class makes up 40% of the final grade
- Moe is failing the class with an average (arithmetic mean) of 45% just before taking the final exam.
From point 1 we know that Moe´s grade just before taking the final exam represents 60% of the final grade. Then, using the information in the point 2 we can compute Moe´s final grade as follows:
,
where FG is Moe´s Final Grade and FE is Moe´s final exam grade. Then,
.
So, in order to receive the passing grade average of 60% for the class Moe needs to obtain in his exam:

That is, he need al least %82.5 to obtain a passing grade.
Answer:
Step-by-step explanation
subtract 8 from both sides
8-2x-8=-4x+4-8
simplify
-2x=-4x-4
add 4x to both sides
-2x+4x=-4x-4+4x
Simplify
2x=-4
divide both sides by 2
2x/2=4/2
simplify
x=-2
Using the z-distribution, as we are working with a proportion, it is found that the 99% confidence interval for the proportion of all U. S. Adults who would include the 9/11 attacks on their list of 10 historic events is (0.7458, 0.7942). It means that we are 99% sure that the true proportion for all U.S. adults is between these two bounds.
<h3>What is a confidence interval of proportions?</h3>
A confidence interval of proportions is given by:

In which:
is the sample proportion.
In this problem, the parameters are:

The lower limit of this interval is:

The upper limit of this interval is:

The 99% confidence interval for the proportion of all U. S. Adults who would include the 9/11 attacks on their list of 10 historic events is (0.7458, 0.7942). It means that we are 99% sure that the true proportion for all U.S. adults is between these two bounds.
More can be learned about the z-distribution at brainly.com/question/25890103