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3 years ago

11

A recipe calls for 1/2 cup of butter for a batch of cookies and makes 24 cookies. How many cups of butter are needed to make 72

cookies?

2 answers:

jolli1 [7]3 years ago

7 0

Answer: 2.5 cups

Step-by-step explanation:

If 1/2 cup makes 24 cookies, and you need 72, divide 72 by 24 and u get 3. So since 72 is 3 things of 24, you multiply 1/2 by 3 which means you need to use 2.5 cups to make 72 cookies.

ehidna [41]3 years ago

7 0

Answer: 1 and 1/2 cups of butter

Step-by-step explanation:

If 24 cookies takes 1/2 cup of butter than 72 divided by 24 is 3 so 1/2 times 3 is 3/2 so it’s 1 and 1/2 cups

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Graph the equation.<br> Y = -4x-5

DerKrebs [107]

Answer:

Make one point at -4,1 and another at 0,-5

Step-by-step explanation:

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3 years ago

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The sum of 3 times a number and 7, divided by 5, is 17 written as an equation

Anestetic [448]

Equation is: $\frac{3x+7}{5}=15$

and Value of x is $x=68/3\\$

Step-by-step explanation:

We need to write an equation of:

The sum of 3 times a number and 7, divided by 5, is 17

Let the number = x

So, equation will be:

$\frac{3x+7}{5}=15$

We can solve the equation to find the value of x.

$\frac{3x+7}{5}=15\\3x+7=15*5\\3x+7=75\\3x=75-7\\3x=68\\x=68/3\\$

So, Equation is: $\frac{3x+7}{5}=15$

and Value of x is $x=68/3\\$

Keywords: Write equation from sentence

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3 years ago

What's the answer for this problem

Svetllana [295]

The answer is 23.2 because you use 29h=672.8

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3 years ago

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Helps mes plzs!!! Its really hard

Likurg_2 [28]

Answer:

0.6

Step-by-step explanation:

-0.2=s+(-0.8)

-0.2=s-0.8

-0.2+0.8=s

s=0.6

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3 years ago

Pam has 90 m of fencing to enclose an area in a petting zoo with two dividers to separate three types of young animals. The thre

andrew-mc [135]

Answer:

The area function is

$A=\frac{135}{2}x-\frac{9}{2}x^2$ .

The domain and range of A is $(0,15m)$ and $(0, 253.125 m^2]$ .

Step-by-step explanation:

The given length of fencing is $90 m$ .

Let the length and width of each pen be $x$ and $y$ respectively as shown in the figure.

As there are 3 pens, so, the total area,

$A= 3 xy \;\cdots (i)$

From the figure the total length of fencing is $6x+4y$ .

Here, for a significant area for the animals, $x>0$ as well as $y>0$ as $x$ and $y$ are the sides of ben.

From the given value:

$6x+4y=90\;\cdots (ii)$

$\Rightarrow y=\frac {45}{2}-\frac{3x}{2}$

Now, from equation (i)

$A=3x\left(\frac {45}{2}-\frac{3x}{2}\right)$

$\Rightarrow A=\frac{135}{2}x-\frac{9}{2}x^2\;\cdots (iii)$

This is the required area function in the terms of variable $x$ .

For the domain of area function, from equation (ii)

$x=15-\frac{2y}{3}$

$\Rightarrow x$ [as y>0]

So, the domain of area function is $(0,15m)$ .

For the range of area function:

As $x \rightarrow 0$ or $y\rightarrow 0$ , then $A\rightarrow 0$ [from equation (i)]

$\Rightarrow A>0$

Now, differentiate the area function with respect to $x$ .

$\frac {dA}{dx}=\frac{135}{2}-9x$

Equate $\frac {dA}{dx}$ to zero to get the extremum point.

$\frac {dA}{dx}=0$

$\Rightarrow \frac{135}{2}-9x=0$

$\Rightarrow x=\frac{15}{2}$

Check this point by double differentiation

$\frac {d^2A}{dx^2}=-9$

As, $\frac {d^2A}{dx^2}$ , so, point $x=\frac{15}{2}$ is corresponding to maxima.

Put this value back to equation (iii) to get the maximum value of area function. We have

$A=\frac{135}{2}\times \frac {15}{2}-\frac{9}{2}\times \left(\frac {15}{2}\right)^2$

$\Rightarrow A=253.125 m^2$

Hence, the range of area function is $(0, 253.125 m^2]$ .

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4 years ago