Answer:
Step-by-step explanation:
no
so we have the points of (0,-7),(7,-14),(-3,-19), let's plug those in the y = ax² + bx + c form, since we have three points, we'll plug each one once, thus a system of three variables, and then we'll solve it by substitution.

well, from the 1st equation, we know what "c" is already, so let's just plug that in the 2nd equation and solve for "b".

well, now let's plug that "b" into our 3rd equation and solve for "a".
![\bf -19=9a-3b-7\implies -12=9a-3b\implies -12=9a-3(-1-7a) \\\\\\ -12=9a+3+21a\implies -15=9a+21a\implies -15=30a \\\\\\ -\cfrac{15}{30}=a\implies \blacktriangleright -\cfrac{1}{2}=a \blacktriangleleft \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{and since we know that}}{-1-7a=b}\implies -1-7\left( -\cfrac{1}{2} \right)=b\implies -1+\cfrac{7}{2}=b\implies \blacktriangleright \cfrac{5}{2}=b \blacktriangleleft \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill y=-\cfrac{1}{2}x^2+\cfrac{5}{2}x-7~\hfill](https://tex.z-dn.net/?f=%5Cbf%20-19%3D9a-3b-7%5Cimplies%20-12%3D9a-3b%5Cimplies%20-12%3D9a-3%28-1-7a%29%20%5C%5C%5C%5C%5C%5C%20-12%3D9a%2B3%2B21a%5Cimplies%20-15%3D9a%2B21a%5Cimplies%20-15%3D30a%20%5C%5C%5C%5C%5C%5C%20-%5Ccfrac%7B15%7D%7B30%7D%3Da%5Cimplies%20%5Cblacktriangleright%20-%5Ccfrac%7B1%7D%7B2%7D%3Da%20%5Cblacktriangleleft%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Band%20since%20we%20know%20that%7D%7D%7B-1-7a%3Db%7D%5Cimplies%20-1-7%5Cleft%28%20-%5Ccfrac%7B1%7D%7B2%7D%20%5Cright%29%3Db%5Cimplies%20-1%2B%5Ccfrac%7B7%7D%7B2%7D%3Db%5Cimplies%20%5Cblacktriangleright%20%5Ccfrac%7B5%7D%7B2%7D%3Db%20%5Cblacktriangleleft%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20~%5Chfill%20y%3D-%5Ccfrac%7B1%7D%7B2%7Dx%5E2%2B%5Ccfrac%7B5%7D%7B2%7Dx-7~%5Chfill)
We have
<span>Va(airplane)=150
East</span>
Vw(wind)=7.1
South East
<span>
</span><span>resulting vector R</span>
airplane
Vax=150 Vay=0 it only has component x
WindVwx=7.1*cos45=5.02
Vwy=7.1*sin45=-5.02
is negative because is South direction
|R|=(Rx^2+Ry^2) ^0.5
Rx=150+5.02=155.02
Ry=0-5.02=-5.02
<span>|R|=155.10
miles/hour South East</span>
Determine angle θ
Rx=R*cos(θ)
<span>Cos(θ)=Rx/R</span>
<span>Cos(θ)=155.02/155.10=0.9995</span>
θ =arc cos Rx/R
θ =1.8119 º
Rx represents the component in the East direction of the resultant force. Your contribution is given by both, the force of the plane and the wind. The contribution of the wind makes the airplane's speed greater
Ry represents the component in the South direction of the resulting force
Its contribution is exclusive of the wind since the airplane has no component
in this direction
|R| the force resulting from the combined action of the force of the plane and the force of the wind
θ represents the angle that forms the resultant force with respect to the x axis or east direction
Answer:
Different substances are made of different PARTICLES.
Some particles JOIN each other more than others, which means that space between the particles is very small.
Answer:
Step-by-step explanation:
We know that f(x) = 2x +4 and g(x) = x -7 so to find f(g(x)) multiply them.
(2x + 4)(x-7) Apply the distributive property twice
2x(x-7)
2x^2 - 14x
4(x-7) = 4x - 28
2x^2 - 14x + 4x -28
2x^2 -10x - 28