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ruslelena [56]
3 years ago
7

Eukaryotes solve the problem of replicating the ends of their linear chromosomes by:

Biology
1 answer:
Nataliya [291]3 years ago
3 0

Answer:

B. Enzyme activity that uses an RNA template and reverse transcription in a series of repeat cycles

Explanation:

In eukaryotic linear chromosomes, the lagging strands at terminal do not get replicated in usual manner because it is a special case. The problem with terminal lagging strand (which is synthesized in a discontinuous manner) is that there is no template for its primer synthesis. In such scenario, an enzyme known as telomerase recognizes telomeres and extend it's 3' overhang through its reverse transcriptase activity which is facilitated by it's RNA component specifically. This RNA has repeat sequences which are complimentary to the telomeric repeats and therefore it acts as a template for the extension of 3' overhang.

Here, it may be noted that the leading strand does not require any terminal primer for replication because the replication process for it is continuous i.e. only one primer is required which is synthesized in the beginning of replication so there is no need of synthesizing primer again and again.

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Bacteria from the soil absorb nitrogen from the air and convert it into ammonium. This is an example of _____.
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<span>Nitrogen fixation

This process creates organic compounds, including ammonium, that contribute to the growth of a plant in much the way fertilizer does. Many plants have evolved to facilitate nitrogen fixing bacteria in their roots as to promote production of these organic compounds when the soil quality is poor or lacking in these bacteria.</span>
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Which of the following is not a renewable resource? select one:
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How might an RNA-based genome result in an increased infection rate? What are some potential complications to this infection str
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Answer:

I think the question is "How might an RNA-based genome results display an increased in infection rate?" because current statement doesn't convey a message clearly.

Explanation:

To answer this question, we need to understand first that what is gene expression. Gene expression is a process in which genetic information is transcribed first to RNA and then into proteins. During transcription stage, only active genes would be transcribed to RNA and all other DNA material don't transcribe at all. Now, if there is an infection, host cell would express only those genes which would actively take part in the defense mechanism, e.g. R-genes, genes involved in production of reactive oxygen species, etc. Hence, to monitor the infection rate, we will look at the RNA-based genome. To do this, we will extract the total RNA and then would sequence it. Then we will annotate the genes and check the relative abundance (differential expression). Finally, we would have a clear that these genes were active against the infection. By doing temporal sampling and sequencing, we would be able to measure the rate as well.

For the second part, potential complications that could arise in doing analysis is the lower amount of RNA, or rapid degradation of RNA in case of presence of RNAses. RNA can be degraded easily at room temperature.

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In the heterozygous state (w+ / w), a variegated eye is produced, with white and red patches. How might one explain position-eff
Yuri [45]

Answer:

2. The white patches are caused by the deacetylation of the histones associated with the DNA of the w + allele.

3. The red patches are caused by the acetylation of the histones associated with the DNA of the w + allele.

Explanation:

The complete question is as follows:

How might one explain position-effect variegation in terms ofhistone acetylation and/or deacetylation? Select all thatapply.

1. The white patches are caused by the acetylation of the histonesassociated with the DNA of the w + allele.

2. The white patches are caused by the deacetylation of thehistones associated with the DNA of the w + allele.

3. The red patches are caused by the acetylation of the histonesassociated with the DNA of the w + allele.

4. The red patches are caused by the deacetylation of the histonesassociated with the DNA of the w + allele.

In the W+/W State variegated eye is produced, however in reality the W+ allele causes a red eye colour whereas the W allele causes a white eye.

The reason for production of variegated eyes is chromosomal rearrangement.

Due to the chromosomal rearrangement the W+ gene's position gets changed and it moves from a region of euchromatin to heterochromatin and this position affect leads to red and white patches in the eye.

The heterochromatin is silent region of the genome which does not encode for any product and this is caused by histone deacetylation whereas the histone acetylation makes the chromosomes more accessible and contributes the euchromatin region.

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