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ruslelena [56]
3 years ago
7

Eukaryotes solve the problem of replicating the ends of their linear chromosomes by:

Biology
1 answer:
Nataliya [291]3 years ago
3 0

Answer:

B. Enzyme activity that uses an RNA template and reverse transcription in a series of repeat cycles

Explanation:

In eukaryotic linear chromosomes, the lagging strands at terminal do not get replicated in usual manner because it is a special case. The problem with terminal lagging strand (which is synthesized in a discontinuous manner) is that there is no template for its primer synthesis. In such scenario, an enzyme known as telomerase recognizes telomeres and extend it's 3' overhang through its reverse transcriptase activity which is facilitated by it's RNA component specifically. This RNA has repeat sequences which are complimentary to the telomeric repeats and therefore it acts as a template for the extension of 3' overhang.

Here, it may be noted that the leading strand does not require any terminal primer for replication because the replication process for it is continuous i.e. only one primer is required which is synthesized in the beginning of replication so there is no need of synthesizing primer again and again.

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When ten or more pre-synaptic neurons conduct impulses to five or fewer post-synaptic neurons, the conduction pattern is said to
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When ten or more pre-synaptic neurons conduct impulses to five or fewer post-synaptic neurons, the conduction pattern is said to be <u>convergent</u>.

A neuron in such a network can take information from numerous other neurons through convergence. Inhibitory interneurons are activated by presynaptic cells, but instead they reduce nearby cells inside the network.

Synaptic divergence refers to the dispersion of synapses from such a single neuron onto several postsynaptic partners as well as partner kinds, while synaptic convergence refers to being affected by having neuronal cell kinds delivering input around on a shared postsynaptic partner.

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1 year ago
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mamaluj [8]

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Explanation:

Mass=0.18kg

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Kinetic energy=(mass x(velocity)^2)➗2

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Kinetic energy=182.25 joules

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