Everything else being equal, write a general expression to show how the exchange current density for a reaction changes as a fun
ction of temperature. In other words, write an expression for j0(T) at an arbitrary temperature T as a function of j0(T0) at a reference temperature T0. If a reaction has j0 = 10-8 A/cm2 at 300K and j0 = 10-4 A/cm2 at 600K, what is ∆G1 + + for the reaction? Assume that the T0 is 300K.
2 answers:
Answer:
Gibbs free energy is 45944.86 J/mol
Explanation:
In Engineering, thermodynamics, the Gibbs free energy is a potential that is used to calculate the maximum of reversible work that may be performed by a thermodynamic system at a constant temperature and pressure.
Please kindly go through the attached file for a rundown of how the answer is gotten.
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Answer:
m = 1.37 lbm
Explanation:
We are given that;
P1 = 90 psia
T1 = 30°F
From the table i attached, at T = 30°F, entropy, s1 = sf = 0.04752 Btu/lbm.R
We are also given;
P2 = 20 psia.
At this, s2 = s1 = 0.04752 Btu/lbm.R
From the table i attached, sf at 20 psia is; sf = 0.02605 Btu/lbm.R and sfg = 0.19962 Btu/lbm.R
Now, formula for quality of steam at Pressure P2 is;
X2 = (s2 - sf)/sfg
Plugging in the relevant values to obtain;
X2 = (0.04752 - 0.02605)/0.19962
X2 = 0.1076
Now, v2 = vf + x2•vfg
From the table i attached, at 20 psia, vf = 0.01182, vg =2.27772 and vfg = vg - vf = 2.27772 - 0.01182 = 2.2659 ft³/lbm
Thus,
v2 = 0.01182 + 0.1076*2.2659 = 0.2556 ft³/lbm
Now, let's find mass of the refrigerant from, m = V/v2
m = 0.35/0.2556 = 1.37 lbm
