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ser-zykov [4K]
4 years ago
13

Air is compressed in the compressor of a turbojet engine. Air enters the compressor at 270 K and 58 kPa and exits the compressor

at 465 K and 350 kPa. Take the average specific heat at constant pressure (cp,avg) of air as 1.015 kJ/ kg.K and Rair = 0.287 kJ/ kg.K. Find the mass specific entropy change associated with the compression process
Engineering
1 answer:
tia_tia [17]4 years ago
8 0

Answer:

Recall the Entropy  Balance (Second Law of Thermodynamics) equations for the system below

And for ideal gas, we know that

Change in Entropy of the air kJ/Kg.K, ΔS = S₁ - S ₂ = Cp Ln (T₂/T₁) - R Ln(P₂/P₁)

where R is gas constant =0.287kJ/kg.K and given

Cp=1.015 kJ/ kg.K

T₂ = 465k T₁=270k, P1=58kPa, P2=350kPa

substituting these values into the eqn above, we have

S = (1.015x 0.544) - (0.287x1.798)

S = 0.0363kJ/Kg.K

Hence, the mass specific entropy change associated with the compression process = 0.0363kJ/Kg.K

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Answer:

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Explanation:

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F = 0.3*475 N

F = 142.5 N (←)

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Explanation:

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3 years ago
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The specific volume of a system consisting of refrigerant-134a at 1.0 Mpa is 0.01 m /kg. The quality of the R-134a is: (a) 12.6%
Flura [38]

Answer:

option c is correct

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Explanation:

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solution

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that is

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Explanation: See above.

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