Answer:
Technician A
Explanation:
Ohms law: I= E/R so rest resistance must be present along with E/potential difference. Even if just wire shorted together there is resistance but very little.
Tech B: Again ohms law. Current flow is directly proportional to the voltage and inversely proportional to R (resistance or impedance).
Answer:
The solution code is written in Java.
- public class Main {
-
- public static void main(String[] args) {
-
- Scanner inNum = new Scanner(System.in);
- System.out.print("Enter number of toss: ");
- int num = inNum.nextInt();
-
- for(int i=0; i < num; i++){
- System.out.println(toss());
- }
- }
-
- public static String toss(){
- String option[] = {"heads", "tails"};
- Random rand = new Random();
- return option[rand.nextInt(2)];
- }
- }
Explanation:
Firstly, we create a function <em>toss()</em> with no parameter but will return a string (Line 14). Within the function body, create an option array with two elements, "heads" and "tails" (Line 15). Next create a Random object (Line 16) and use <em>nextInt()</em> method to get random value either 0 or 1. Please note we need to pass the value of 2 into <em>nextInx() </em>method to ensure the random value generated is either 0 or 1. We use this generate random value as an index of <em>option </em>array and return either "heads" or "tails" as output (Line 17).
In the main program, we create Scanner object and use it to prompt user to input an number for how many times to toss the coin (Line 6 - 7). Next, we use the input num to control how many times a for loop should run (Line 9). In each round of the loop, call the function <em>toss() </em>and print the output to terminal (Line 10).
Answer: Option D, piezoelectric pressure guage
Explanation: Quartz crystal possess a very useful quality in science as they can generate small charges when pressure is applied to them or when they are hit. This property can be harnessed to construct a piezoelectric pressure gauge which would be used to measure and indicate changes in pressure, the quartz crystal releases little voltage each time there is an applied pressure . This device would be able to sense changes in pressure as there would voltage proportional to the applied pressure.
Answer:
Crean un código usando la naturaleza.
