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kolezko [41]
3 years ago
5

Simplify. –20 + (–2) • (–6) = A. –132 B. –32 C. –8 D. 132

Mathematics
2 answers:
Ray Of Light [21]3 years ago
7 0
C. = -8
(-2) x (-6) =12
(12) - (20) = -8
Dmitrij [34]3 years ago
6 0
-20 + (-2)(-6) = 

= -20 + (12)

= -8

The answer is C. -8
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UkoKoshka [18]
1/3 is in fact NOT larger than 4/5. 4/5 is larger than 1/3.
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4 years ago
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13,000 inches equals how many miles
Nataly [62]

Answer:

0.205177 mi

Step-by-step explanation:

Step 1: Find conversions

12 in = 1 ft

5280 ft = 1 mi

Step 2: Use Dimensional Analysis

13000 \hspace{2} in(\frac{1 \hspace{2} ft}{12 \hspace{2} in} )(\frac{1 \hspace{2} mi}{5280 \hspace{2} ft} )

0.205177 mi

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3 years ago
The function h(x) is defined as shown.
belka [17]
Hello,

h(x)= if x<3 then x+2
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Answer B






7 0
3 years ago
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he number of surface flaws in plastic panels used in the interior of automobiles has a Poisson distribution with a mean of 0.02
Yakvenalex [24]

Answer:

a) 98.01%

b) 13.53\%

c) 27.06%

Step-by-step explanation:

Since a car has 10 square feet of plastic panel, the expected value (mean) for a car to have one flaw is 10*0.02 = 0.2  

If we call P(k) the probability that a car has k flaws then, as P follows a Poisson distribution with mean 0.2,

P(k)= \frac{0.2^ke^{-0.2}}{k!}

a)

In this case, we are looking for P(0)

P(0)= \frac{0.2^0e^{-0.2}}{0!}=e^{-0.2}=0.9801=98.01\%

So, the probability that a car has no flaws is 98.01%

b)

Ten cars have 100 square feet of plastic panel, so now the mean is 100*0.02 = 2 flaws every ten cars.

Now P(k) is the probability that 10 cars have k flaws and  

P(k)= \frac{2^ke^{-2}}{k!}

and  

P(0)= \frac{2^0e^{-2}}{0!}=0.1353=13.53\%

And the probability that 10 cars have no flaws is 13.53%

c)

Here, we are looking for P(1) with P defined as in b)

P(1)= \frac{2^1e^{-2}}{1!}=2e^{-2}=0.2706=27.06\%

Hence, the probability that at most one car has no flaws is 27.06%

6 0
3 years ago
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A certain big company classifies its employees according to gender, age-group (6 categories) and employment type (10 categories)
elena-14-01-66 [18.8K]

We don’t know the number of employees remaining at the company.

We don’t know the total number of employees remaining at the company.

The classification consists of gender, division, and employment type.

It doesn’t matter what order those attributes come in. A person who is male, age group 6, and employment type 10 has the same classification as someone who is of employment type 6, male, and age group10.

Therefore since order does not matter it is a combination question.

Assuming only two genders are allowed (you didn’t say and some people think there are about 10 of them)

It is either 120 (2 times 6 times 10) or "None of the above" if you believe there are more than 2 genders.

2×6×10=120

Learn more about employees at

brainly.com/question/1190099

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3 0
2 years ago
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