Answer:
Molecular Formula == Empirical Formula
A.)C₄H₈O₂ 3.) C₂H₄O
B.)C₄H₁₂O₄ 1.) CH₃O
C.)C₂H₁₀O₂ 2.) CH₅O
Explanation:
Data Given
Molecular Formula
A.)C₄H₈O₂
B.)C₄H₁₂O₄
C.)C₂H₁₀O₂
Empirical Formula
1.) CH₃O
2.) CH₅O
3.) C₂H₄O
Match each molecular formula to the corresponding empirical formula = ?
Solution:
As we know
Empirical formula shows the simplest ratio of atoms in the molecule but not whole numbers of atoms in a compound or molecule
So we look at the ratio of atoms in each given molecule and will find the simplest ratio
A.)C₄H₈O₂
Look at the ratio of atoms
C : H : O
4 : 8 : 2
Divide the all values on the smallest values to get simplest number ratio
C : H : O
4/2 : 8/2 : 2/2
2 : 4 : 1
So the simplest ratio of carbon, hydrogen and oxygen is 2, 4 and 1 respectively
C : H : O
2 : 4 : 1
so the empirical formula will be
3.) C₂H₄O
The match pair will be
Molecular formula == Empirical formula
C₄H₈O₂ C₂H₄O
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B.)C₄H₁₂O₄
Look at the ratio of atoms
C : H : O
4 : 12 : 4
Divide the all values on the smallest values to get simplest number ratio
C : H : O
4/4 : 12/4 : 4/4
1 : 3 : 1
So the simplest ratio of carbon, hydrogen and oxygen is 1, 3 and 1 respectively
C : H : O
1 : 3 : 1
so the empirical formula will be
1.) CH₃O
The match pair will be
Molecular formula == Empirical formula
C₄H₁₂O₄ CH₃O
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C.)C₂H₁₀O₂
Look at the ratio of atoms
C : H : O
2 : 10 : 2
Divide the all values on the smallest values to get simplest number ratio
C : H : O
2/2 : 10/2 : 2/2
1 : 5 : 1
So the simplest ratio of carbon, hydrogen and oxygen is 1, 5 and 1 respectively
C : H : O
1 : 5 : 1
so the empirical formula will be
2.) CH₅O
The match pair will be
Molecular formula == Empirical formula
C₂H₁₀O₂ CH₅O
