The answer will be 7.50 because you are doing your times if you do divid its going to be hard so times to get your answer.
Answer:
y=-3/4x-5
Step-by-step explanation:
m=y2-y1/x2-x1
m=1-(-5)/-8-0
m=1+5/-8
m=6/-8
m=-3/4
y-y1=m(x-x1)
y-(-5)=-3/4(x-0)
y+5=-3/4x
y=-3/4x-5
On drawing , we have scale of 2 yard = 1 inch
so sides must be 6 inch, 7 inch, 8 inch and 9 inch !!
( just divide ) !!
if you got any problem, comment !!
If tan(<span>θ) is negative, then </span><span>θ must be either in Q-II or else in Q-IV.
Fortunately, the question tells us that it's in Q-II.
If you draw a circle on the x- and y-axes, then draw a right triangle
in Q-II, then mark the legs 3 and -2, then the hypotenuse of the
triangle ... also the radius of the circle ... is √13 .
Look for the angle whose tangent is -3/2.
tangent = (opposite) / (adjacent)
So the side opp</span>osite is the 3 and the side adjacent is the -2.
For that same angle, cosine = (adjacent) / (hypotenuse) .
The adjacent side is still the -2, and the hypotenuse is √13 .
So the cosine of the same angle is
- 2 / √13 .
To rationalize the denominator (get that square root out of there),
multiply top and bottom by √13 . Then you have
(- 2 / √13) · (√13 / √13)
= - 2 √13 / 13 .
