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yaroslaw [1]
3 years ago
14

Help me plz with my math homework

Mathematics
1 answer:
enyata [817]3 years ago
6 0
86-(5+9)
————- =
3

86-(14)
———- =
3

72
—- = 24
3

45-(11+9)
————- =
5

45-(20)
———— =
5

25
—— = 5
5
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PLEASE HELP ASAP 20 POINTS!!!!!!
tankabanditka [31]
Number 1.
Subtracting Negative Is The Same As Adding.
<span>So, It Would Be Equivalent  To A
</span>Number 2:
Subtracting From A Negative Is Making The Negative Number Larger.
<span>So, It Would Be A
</span>Number 3:
<span>Positive Plus Positive Makes Larger Positive:
37 + 13 = 50</span>.
<span>So, 3 Is D.
Number 4:
</span>Adding Negative Is Making Positive Numbers Smaller.
So, It Is C.
Number 5:
This Is C, Because -30 + 30 = 0 + 1 = 1 
4 0
3 years ago
Read 2 more answers
A midwestern music competition awarded 38 ribbons. The number of blue ribbons awarded was 1 less than the number of white ribbon
Artist 52 [7]
Starting from what I know (the difference between ribbons), I decided to go from the bottom and work my way up. I then noticed a pattern (each sum was three more of the previous one), and decided to keep my pattern of the three numbers but not have to do any major mental work and instead add three to the previous sum until I got to 38.

4 0
3 years ago
You throw a ball up and its height h can be tracked using the equation h=2x^2-12x+20.
postnew [5]

<em><u>This problem seems to be wrong because no minimum point was found and no point of landing exists</u></em>

Answer:

1) There is no maximum height

2) The ball will never land

Step-by-step explanation:

<u>Derivatives</u>

Sometimes we need to find the maximum or minimum value of a function in a given interval. The derivative is a very handy tool for this task. We only have to compute the first derivative f' and have it equal to 0. That will give us the critical points.

Then, compute the second derivative f'' and evaluate the critical points in there. The criteria establish that

If f''(a) is positive, then x=a is a minimum

If f''(a) is negative, then x=a is a maximum

1)

The function provided in the question is

h(x)=2x^2-12x+20

Let's find the first derivative

h'(x)=4x-12

solving h'=0:

4x-12=0

x=3

Computing h''

h''(x)=4

It means that no matter the value of x, the second derivative is always positive, so x=3 is a minimum. The function doesn't have a local maximum or the ball will never reach a maximum height

2)

To find when will the ball land, we set h=0

2x^2-12x+20=0

Simplifying by 2

x^2-6x+10=0

Completing squares

x^2-6x+9+10-9=0

Factoring and rearranging

(x-3)^2=-1

There is no real value of x to solve the above equation, so the ball will never land.

This problem seems to be wrong because no minimum point was found and no point of landing exists

3 0
3 years ago
How do you solve this equation?
Natasha2012 [34]

Answer:

5 \sqrt{2}

= 7.071067812

Step-by-step explanation:

hope this helps

8 0
2 years ago
One three and six are traingular list all the other triangular numbers up to 36
ArbitrLikvidat [17]
That isn’t a question it is a statement
3 0
3 years ago
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