Which weight group lumps have the greatest total weight

Mathematics

1 answer:

Romashka [77]3 years ago

4 0

Let us make the denominators all the same so we can compare the fractions easily. We have 1/8, 1/4, 1/2, 5/8, and 7/8. It will be easiest if we change the denominators to 8. Three of the fractions already have a denominator of 8, so we only have to change two. 1/2 equals 2/4 equals 4/8. 1/4 equals 2/8.

Now we can compare the fractions easily. We have 1/8, 2/8, 4/8, 5/8, and 7/8. We see that 7/8 is the greatest fraction.

I hope that this helped you!

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Solve the equatuon<br><br> x/2-(2/(x+1))=1<br><br> x=?

Snezhnost [94]

$\frac{x}{2}-\frac{2}{x+1}=1$

We have 2 denominators that we need to get rid of. Whenever there are the denominators, all we have to do is multiply all whole equation with the denominators.

Our denominators are both 2 and x+1. Therefore, we multiply the whole equation by 2(x+1)

$\frac{x}{2}[2(x+1)]-\frac{2}{x+1}[2(x+1)] = 1[2(x+1)]$

Then shorten the fractions.

$\frac{x}{2}[2(x+1)]-\frac{2}{x+1}[2(x+1)] = 1[2(x+1)]\\x(x+1)-2(2)=1(2x+2)$

Distribute in all.

$x^2+x-4=2x+2$

We should get like this. Because the polynomial is 2-degree, I'd suggest you to move all terms to one place. Therefore, moving 2x+2 to another side and subtract.

$x^2+x-4-2x-2=0\\x^2-x-6=0\\$

We are almost there. All we have to do is, solving for x by factoring. (Although there are more than just factoring but factoring this polynomial is faster.)

$(x-3)(x+2)=0\\x=3,-2$