A) 363 B) 33 C) 7 D) 77

The graph of a quadratic relationship is in the shape of a parabola. Parabolas are symmetric arcs and are useful for modeling re

zhuklara [117]

Answer:

The arcs on the Golden Gate Bridge.

Explanation:

I think about the Golden Gate Bridge, which is a suspension bridge.

As in any suspension bridge, a long cable is supported by two large supports.

The cable falls from a support, in the form of a curve concave upwards, to a minimum point that is the vertex of the parabola, through which the axis of symmetry passes, and curves again upwards to ascend to the upper end of the other support.

As a unique feature of this parabolic arc you can tell that the the concavity is upward; the parabola open upward.

Also, you can tell that the parabola is vertical, which means that the axis of symmetry is vertical.

The symmetry is clear because to the curve to the left of the vertex is a mirror image of the curve to the right of the vertex.

6 0

4 years ago

10.) state whether the given side lengths can form a triangle

Verizon [17]

Answer:

A. 5,8,12, side lengths can form a triangle.

B. 20, 18, 2, side lengths can not form a triangle.

C. 15, 26 , 9, side lengths can not form a triangle.

D. 4.75, 12.25, 16.25, side lengths can form a triangle.

Step-by-step explanation:

We are given three sides in options A, B , C and D.

We need to check if the given sides would form a triangle or not.

Note: Sum of two sides is always greater than third sides in a triangle.

So, we need to check the sum of two sides of given sides length to check if sum is greater than third side length.

A. 5,8,12.

5+8 is greater than 12.

5+12 is greater than 8.

12+8 is greater than 5.

Therefore A. 5,8,12, side lengths can form a triangle.

B. 20, 18, 2

18+2 is not greater than 20.

Therefore B. 20, 18, 2, side lengths can not form a triangle.

C. 15, 26 , 9

15+9 is less than 26.

Therefore C. 15, 26 , 9, side lengths can not form a triangle.

D. 4.75, 12.25, 16.25.

4.75+12.25 is greater than 16.25.

4.75+16.25 is greater than 12.25.

12.25+16.25 is greater than 4.75.

Therefore D. 4.75, 12.25, 16.25, side lengths can form a triangle.

3 0

3 years ago

Michael is 4 times as old as Brandon and is also 27 years older than Brandon.

kiruha [24]

I’m kinda confused on what the question is but michael is 108 if that’s what your asking

7 0

3 years ago

Read 2 more answers

Consider parallelogram ABCD. Which of the following transformations will change the perimeter of the parallelogram?

jeka57 [31]

In geometry, transformation involves changing the position and/or size of a shape.

The transformation that will change the size of ABCD is dilation.

There are four transformations in geometry:

Translation
Reflection
Rotation
Dilation

Of all types of transformation, dilation will change the size of the shape,

The new shape will either be enlarged or reduced

Either ways, the size of the shape will be altered.

When the size is altered, the perimeter will not remain the same.

Hence. dilation will change the perimeter of ABCD.

Read more about transformations at:

brainly.com/question/11709244

4 0

2 years ago

Solve using algebraic equation: 5sin2x=3cosx (No exponents)

DaniilM [7]

$5\sin2x=3\cos x\iff10\sin x\cos x=3\cos x$

by the double angle identity for sine. Move everything to one side and factor out the cosine term.

$10\sin x\cos x=3\cos x\iff10\sin x\cos x-3\cos x=\cos x(10\sin x-3)=0$

Now the zero product property tells us that there are two cases where this is true,

$\begin{cases}\cos x=0\\10\sin x-3=0\end{cases}$

In the first equation, cosine becomes zero whenever its argument is an odd integer multiple of $\dfrac\pi2$ , so $x=\dfrac{(2n+1)\pi}2$ where $n[/tex ]is any integer.\\Meanwhile,\\[tex]10\sin x-3=0\implies\sin x=\dfrac3{10}$

which occurs twice in the interval $[0,2\pi)$ for $x=\arcsin\dfrac3{10}$ and $x=\pi-\arcsin\dfrac3{10}$ . More generally, if you think of $x$ as a point on the unit circle, this occurs whenever $x$ also completes a full revolution about the origin. This means for any integer $n$ , the general solution in this case would be $x=\arcsin\dfrac3{10}+2n\pi$ and $x=\pi-\arcsin\dfrac3{10}+2n\pi$ .

6 0

3 years ago