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Digiron [165]
3 years ago
8

A salesman bought 2 dozen television sets at $300 each. He sold two-thirds of them at

Mathematics
2 answers:
Kipish [7]3 years ago
8 0
Well, the first 16 were about 16*75=$1200 extra. The last 8 were $720 lost. Thus, the total profit is $480. He bought them with $7200, which means the profit is around 6.67%.
Alja [10]3 years ago
3 0

Answer: A salesman bought 2 dozen television sets at $300 each. He sold two-thirds of them at a 25% profit but was forced to take a 30% loss on the rest. what was his total profit(or loss) on the television sets?

----

Original cost 24*300 = 7200

----

Profit: 0.25*(2/3)24*300 = 1200

---

Loss: 0.3*(1/3)24*300 = 720

----

Total profit = 1200-720 = $480

Step-by-step explanation:

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Country days scholarship rounds receive a gift of $135000. The money is invested in stock, bonds, and CDs. CDs pay 2.75% interes
Vsevolod [243]

Answer:

  • CDs — $10,000
  • bonds — $80,000
  • stocks — $45,000

Step-by-step explanation:

Let the variables c, b, s represent the dollar amounts invested in CDs, stocks, and bonds, respectively. Then the problem statement gives us 3 relations between these 3 variables:

  c + b + s = 135000 . . . . . . . . . . . . . . . . . total invested

  0.0275c +.045b +0.104s = 8555 . . . . . total income earned

  -c + b = 70000 . . . . . . . . . . . . . . . . . . . . . 70,000 more was in bonds than CDs

Using the third equation to write an expression for b, we can substitute into the other two equations.

  b = 70000 +c . . . . . . . . . . . . . . . . expression we can substitute for b

  c + (70000 +c) +s = 135000 . . . . substitute for b in the first equation

  2c +s = 65000 . . . . . . . . . . . . . . . . [eq4] simplify

  .0275c +.045(70000 +c) +.104s = 8555 . . . . . substitute for b in 2nd eqn

  .0725c +.104s = 5405 . . . . . . . . . . [eq5] simplify

Using [eq4], we can write an expression for s that can be substituted into [eq5].

  s = 65000 -2c . . . . . . . expression we can substitute for s

  0.0725c +0.104(65000 -2c) = 5405

  -0.1355c = -1355 . . . . . . . . . . . . . . . . . . . . subtract 6760, simplify

  c = 1355/.1355 = 10,000

  s = 65000 -2×10000 = 45,000

  b = 70000 +10000 = 80,000

The amounts invested in stocks, bonds, and CDs were $45,000, $80,000, and $10,000, respectively.

_____

Alternatively, you can reduce the augmented matrix for this problem to row-echelon form using any of several calculators or on-line sites. That matrix is ...

\left[\begin{array}{ccc|c}1&1&1&135000\\0.0275&0.045&0.104&8555\\-1&1&0&70000\end{array}\right]

6 0
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Galina-37 [17]

Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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