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shtirl [24]
3 years ago
6

What is the solution to Negative 1 minus 7? A number line going from negative 10 to positive 10. –8 –6 6 8

Mathematics
2 answers:
Rzqust [24]3 years ago
8 0

Answer:

-8

Step-by-step explanation:

plug it into a calculator. its taking 7 away from an already negative number.

Lemur [1.5K]3 years ago
8 0

Answer:

-8

Step-by-step explanation:

teehee

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Explanation:
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3 years ago
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The answer is $4.78 

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4 0
3 years ago
Please calculate this limit <br>please help me​
Tasya [4]

Answer:

We want to find:

\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n}

Here we can use Stirling's approximation, which says that for large values of n, we get:

n! = \sqrt{2*\pi*n} *(\frac{n}{e} )^n

Because here we are taking the limit when n tends to infinity, we can use this approximation.

Then we get.

\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n} = \lim_{n \to \infty} \frac{\sqrt[n]{\sqrt{2*\pi*n} *(\frac{n}{e} )^n} }{n} =  \lim_{n \to \infty} \frac{n}{e*n} *\sqrt[2*n]{2*\pi*n}

Now we can just simplify this, so we get:

\lim_{n \to \infty} \frac{1}{e} *\sqrt[2*n]{2*\pi*n} \\

And we can rewrite it as:

\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n}

The important part here is the exponent, as n tends to infinite, the exponent tends to zero.

Thus:

\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n} = \frac{1}{e}*1 = \frac{1}{e}

7 0
3 years ago
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Rzqust [24]

Answer:

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Step-by-step explanation:

4 0
3 years ago
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miv72 [106K]

Answer:

The answer is D

Step-by-step explanation:

  • Let's see all choices in detail

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B .It seems like rational number but it is not simplified yet so -18 \ 2= -9

C .

\sqrt{9}  = 3 \: so \: it \: is \: also \: integer

D . 4\5 it is decimal so it is rational number not integer

I hope u like it

4 0
3 years ago
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