Answer:
The square roots of 49·i in ascending order are;
1) -7·(cos(45°) + i·sin(45°))
2) 7·(cos(45°) + i·sin(45°))
Step-by-step explanation:
The square root of complex numbers 49·i is found as follows;
x + y·i = r·(cosθ + i·sinθ)
Where;
r = √(x² + y²)
θ = arctan(y/x)
Therefore;
49·i = 0 + 49·i
Therefore, we have;
r = √(0² + 49²) = 49
θ = arctan(49/0) → 90°
Therefore, we have;
49·i = 49·(cos(90°) + i·sin(90°)
By De Moivre's formula, we have;
Therefore;
√(49·i) = √(49·(cos(90°) + i·sin(90°)) = ± √49·(cos(90°/2) + i·sin(90°/2))
∴ √(49·i) = ± √49·(cos(90°/2) + i·sin(90°/2)) = ± 7·(cos(45°) + i·sin(45°))
√(49·i) = ± 7·(cos(45°) + i·sin(45°))
The square roots of 49·i in ascending order are;
√(49·i) = - 7·(cos(45°) + i·sin(45°)) and 7·(cos(45°) + i·sin(45°))
The answer is 25 since ADC=125 and ADC+DCB=180. You get DCB=55 and then m1-m2 = 55 so it’s 25
Answer:
The minimum point is (4.5, -1.25).
Step-by-step explanation:
x^2+19=9x
= x^2 - 9x + 19 = 0
Convert to Vertex form:
(x - 4.5)^2 - 4.5^2 + 19 = 0
= (x - 4.5)^2 - 1.25.
The minimum point is (4.5, -1.25).
A bag contains only red , blue , white and black counters. The number of white is the same as the number of black. The table shows the probability of red or blue counter being chosen at random. The bag contains 240 counters work out how many white counters there are in a bag
Answer:
The other pairs are:
and
and
and
See attachment for plots
Step-by-step explanation:
Given
Solving (a): Plot a, b and c
See attachment for plots
Solving (b): Find other pairs for and
The general rule is that:
The other points can be derived using
and
Let ---- You can assume any value of n
So, we have:
So, the pairs are:
Take LCM
And
Take LCM
The other pairs are:
and
So, the pairs are:
Take LCM
And
Take LCM
The other pairs are:
and
So, the pairs are
Take LCM
And
Take LCM
So, the other pairs are:
and