3 years ago

It takes karina 36 minutes to solve 22 problems. What is her unit rate in problems per minute

Mathematics

1 answer:

andrezito [222]3 years ago

6 0

11/18 or .61111111...

You might be interested in

Which situation is best described by the graph shown?

kramer

Where’s the graph???

8 0

3 years ago

Write each expression as a single power of 10

swat32

Answer:

It is

${10}^{5}$

Step-by-step explanation:

$\frac{ {10}^{4}. {10}^{5} . {10}^{6} }{ {10}^{3} . {10}^{7} } = \frac{ {10}^{(4 + 5 + 6)} }{ {10}^{(3 + 7)} } \\ \\ = \frac{ {10}^{15} }{ {10}^{10} } \\ \\ = {10}^{(15 - 10)} \\ = {10}^{5}$

3 0

3 years ago

In the mall 1/15 of the stores sell shoes. There are 180 stores in the mall. How many of the stores sell shoes.

Degger [83]

Answer:

12 stores

Step-by-step explanation:

180 * 1/15 = 180/15 = 12

4 0

3 years ago

Read 2 more answers

Integers- Question 4 a-b

gregori [183]

Hope I was able to help.

6 0

3 years ago

Mr. Snow bought 90 grams of Christmas candy for each of his 14 grandchildren. How many total kilograms of candy did he buy?

nignag [31]

Answer:

1.26 kg.

Step-by-step explanation:

We have been given that Mr. Snow bought 90 grams of Christmas candy for each of his 14 grandchildren. We are asked to find the amount of candy bought by Mr. Snow in kilograms.

First of all, we will find the amount of candy in grams by multiplying 90 grams by 14 as:

$\text{Amount of candy bought in grams}=14\times 90$

$\text{Amount of candy bought in grams}=1260$

We know that 1 kilogram is equal to 1000 grams. To convert 1260 grams into kg, we will divide 1260 by 1000 as:

$\text{Amount of candy bought in kilograms}=\frac{1260}{1000}$

$\text{Amount of candy bought in kilograms}=1.26$

Therefore, Mr. Snow bought 1.26 kilograms of candy.

7 0

3 years ago