Answer:
perpendicular
Step-by-step explanation:
start but putting each line into the standard line format
2x-y=-5
-y=-2x-5
y=2x+5
x+2y=-6
2y=-x-6
y=-(1/2)x-3
if lines are parallel the slopes would be the same. 2 is not equal to -1/2
if lines are perpendicular the slope of one would be the opposite inverse of the other.
negative inverse of 2 = - (1/2)
so the lines are perpendicular
Answer:
(5√5)(6√4) = 5 * √5 * 6 * 2 = 60*√5
We have to assume that the speed before being stuck was sufficient to get to the destination on time had there been no delay. Call that speed "s" in km/h.
Since 200 km is "halfway", the total distance must be 400 km.
time = distance / speed
total time = (time for first half) + (delay) + (time for second half)
400/s = 200/s + 1 + 200/(s+10) . . . .times are in hours, distances in km
200/s = 1 + 200/(s+10) . . . . . . . . . . subtract 200/s
200(s+10) = s(s+10) +200s . . . . . . .multiply by s(s+10)
0 = s² +10s - 2000 . . . . . . . . . . . . . .subtract the left side
(s+50)(s-40) = 0
Solutions are s = -50, s = 40
The speed of the bus before the traffic holdup was 40 km/h.
The ratio of dye to pounds of clothing is constant. A worker develops the chart below to show the amount of dye needed for different amounts of clothing. Clothes Dyeing Weight of clothing (pounds) Cups of dye 22 5.5 28 6.5 34 8.5 36 9 For which weight of clothing is the ratio of weight to dye different from the other ratios?
