There are 62 quarters and 52 dimes in the jar.
Step-by-step explanation:
Given,
Worth of jar coins = $20.70 = 20.70*100 = 2070 cents
1 Quarter = 25 cents
1 Dime = 10 cents
Let,
Number of quarters = x
Number of dimes = y
According to given statement;
25x+10y=2070 Eqn 1
x=y+10 Eqn 2
Putting value of x from Eqn 2 in Eqn 1

Dividing both sides by 35

Putting y=52 in Eqn 2

There are 62 quarters and 52 dimes in the jar.
Keywords: linear equation, substitution method
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Simplifying
2x2 + 6x + 4 = 24
Reorder the terms:
4 + 6x + 2x2 = 24
Solving
4 + 6x + 2x2 = 24
Solving for variable 'x'.
Reorder the terms:
4 + -24 + 6x + 2x2 = 24 + -24
Combine like terms: 4 + -24 = -20
-20 + 6x + 2x2 = 24 + -24
Combine like terms: 24 + -24 = 0
-20 + 6x + 2x2 = 0
Factor out the Greatest Common Factor (GCF), '2'.
2(-10 + 3x + x2) = 0
Factor a trinomial.
2((-5 + -1x)(2 + -1x)) = 0
Ignore the factor 2.
Subproblem 1
Set the factor '(-5 + -1x)' equal to zero and attempt to solve:
Simplifying
-5 + -1x = 0
Solving
-5 + -1x = 0
Move all terms containing x to the left, all other terms to the right.
Add '5' to each side of the equation.
-5 + 5 + -1x = 0 + 5
Combine like terms: -5 + 5 = 0
0 + -1x = 0 + 5
-1x = 0 + 5
Combine like terms: 0 + 5 = 5
-1x = 5
Divide each side by '-1'.
x = -5
Simplifying
x = -5
267+21 = 288
288/9 = 32
the answer is 32 people will ride on each bus