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sergiy2304 [10]
3 years ago
11

(-4, -2),(-18,7) slope

Mathematics
1 answer:
Nuetrik [128]3 years ago
3 0

Slope = (7 + 2)/(-18 + 4) = 9/-14= - 9/14

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Kay [80]
(meal volunteers) = \frac{9}{16}(total volunteers)
36 = \frac{9}{16}(total volunteers)
\frac{16}{9}*36 = (total volunteers)
64 = total volunteers
5 0
4 years ago
A company has found that the daily demand x for its boxes of chocolates is inversely proportional to the price p. When the price
Amiraneli [1.4K]

Answer:

667 boxes

Step-by-step explanation:

-Given that x is the demand and p the price.

-Let  k be the constant of proportionality. We then express the inverse relationship as:

x=\frac{k}{p}\\\\k=xp=800\times 5=4000

#We substitute for the new x value and the calculated k to solve for p:

x=\frac{k}{p}\\\\p=\frac{k}{x}\\\\=\frac{4000}{6}\\\\=666.6667\\\\\approx 667\  boxes

Hence, the demand at a price of $6 is approximately 667 boxes

3 0
3 years ago
Please answer it now in two minutes
ziro4ka [17]
The correct answer is 4

Step by step is blew

Hopefully this help you

3 0
3 years ago
Read 2 more answers
Please help I don't understand this thank you
VikaD [51]
Angle QPS is an inscribed angle.  Arc QS is the intercepted arc of that angle.  The rule is that the intercepted arc is twice its angle measure.  P measures 20 degrees, so arc QS measures 40 degrees.  It just so happens that angle QTS is ALSO an inscribed angle intercepting arc QS.  So angle QTS measures the same as angle P, 20 degrees.  That's a.  For b., we already stated the rule and figured out that minor arc QS is 40 degrees.  For c., major arc QTS is 360 (the measure around the outside of a circle...EVERY circle in the world) minus the minor arc of 40.  So major arc QTS measures 360 - 40 which is 320 degrees.  There you go!
6 0
4 years ago
The length of a rectangle is 4 meters less than twice its width. The are of a rectangle is 70m^2. Find the dimensions of the rec
igomit [66]

Answer:

The length is 7 m

The width is 10 m

Step-by-step explanation:

length = x

width = 2x - 4

length * width = area

It is given that the area is 70 m^{2}

From there

x * (2x - 4) = 70

2x^{2} - 4x = 70

2x^{2} - 4x - 70 = 0

x^{2} - 2x - 35 = 0

Now we have a quadratic equation, which is  ax^{2} + bx + c = 0, where a \neq 0

In this equation a = 1, b = -2 and c = -35

Discriminant (D) formula is b² - 4ac

D = -2^{2}  - 4 * 1 * (-35) = 144 > 0

This discriminant is more than 0, so there are two possible x

Their formulas are  \frac{- b - \sqrt{D}  }{2a} and \frac{- b + \sqrt{D}  }{2a}

x_{1} =  \frac{- (-2) - \sqrt{144} }{2} = -5 < 0 (the length of the rectangle has to be more than 0, so we don't use this x)

x_{2} = \frac{- (-2) + \sqrt{144} }{2} = 7 > 0 (this one is right)

Calculating the dimensions

length = x = 7 (m)

width = 2x - 4 = 2 * 7 - 4 = 10 (m)

8 0
3 years ago
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