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Tatiana [17]
3 years ago
11

Instead of using the values {1,2,3,4,5,6} on dice, suppose a pair of dice have the following: {1,2,2,3,3,4} on one die and {1,3,

4,5,6,8} on the other. Find the probability of rolling a sum of 9 with these dice. Be sure to reduce.

Mathematics
2 answers:
Airida [17]3 years ago
8 0

Answer: 1/9

Step-by-step explanation:

ICE Princess25 [194]3 years ago
3 0

Answer: 1/9

Step-by-step explanation: Of the 36 possible sums, 4 of them are 9. The probability is 4/36 = 1/9.

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How do i do this and tell me how u got the answer
EastWind [94]
Substitute.
2x+(2x -15) = -3

4x -15 = -3
Add 15 to both sides

4x = 12

Divide by 4

X=3

2(3) + y = -3

6+y=-3
-6 from both sides
Y=-9

(3,-9)
3 0
3 years ago
PLS. HELP. ME
klemol [59]

Answer:

C. 1.75

Step-by-step explanation:

7 paved over 4 unpaved

7 divided by 4

1.75

6 0
3 years ago
2x - 5y = 16<br> x - 2y = 5<br> elimination?
harina [27]

Answer:

Y = 6

X = 24

Step-by-step explanation:

2x -5y = 16

(x -2y =5)*2

_______________

2x -5y = 16

2x - 4y = 10

_______________

(2x -5y = 16) - (2x - 4y = 10)

_______________

0x -y = 6

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y =6

_______________

Replacing in equation 1:

2x - 5(6) = 16

so, 2x = 16 + 30

2x = 48

x = 24

6 0
3 years ago
Predator and prey difference<br>​
podryga [215]

Answer:

predator killed animals to eat and prey is described as organism that predator kill for food.

5 0
3 years ago
What value is equivalent to:<br> (8*4*2/8*7)^2 x (8^0/7^-3)^3 x 7^-9???
ankoles [38]

(8*4*2/8*7)^2 x (8^0/7^-3)^3 x 7^-9

Simplify the equations:

(8*4*2/8*7)^2 = (64/56)^2 = (8/7)^2

(8^0/7^-3)^3 = (1/7^-3)^3 = 7^9

Now you have :

(8/7)^2 x 7^9 x 7^-9

Multiply 7^9 x 7^-9 by adding the exponents to get 7^0, which = 1

Now you have:

(8/7)^2 x 1

(8/7)^2 = (8x8) / (7x7) = 64/49

64/49 x 1 = 64/49

6 0
3 years ago
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