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2 years ago

What element is being oxidized in the following redox reaction?

Chemistry

1 answer:

DIA [1.3K]2 years ago

8 0

Answer:

The element that has been oxidized is the N

Explanation:

Zn²⁺(aq) + NH₄⁺(aq) → Zn(s) + NO₃⁻(aq)

See all the oxidation states:

Zn²⁺ → acts with +2

In ammonia, H acts with +1 and N with -3

Zn(s), acts with 0. In all the elements in ground state, the oxidation state is 0.

Zn changed from 2+ to 0. The oxidation number, has decreased.

This element has been reduced.

NO₃⁻ (aq) it's a ion, from nitric acid.

N acts with +5

O acts with -2

The global charge is -1

The N, has increased the oxidation state, so this element is the one oxidized.

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How do you separate alcoh0l from water?

Xelga [282]

Answer:

Fractional distillation

Explanation:

7 0

2 years ago

Solid NaBr is slowly added to a solution that is 0.073 M in Cu+ and 0.073 M in Ag+.Which compound will begin to precipitate firs

saul85 [17]

Answer :

AgBr should precipitate first.

The concentration of $Ag^+$ when CuBr just begins to precipitate is, $1.34\times 10^{-6}M$

Percent of $Ag^+$ remains is, 0.0018 %

Explanation :

$K_{sp}$ for CuBr is $4.2\times 10^{-8}$

$K_{sp}$ for AgBr is $7.7\times 10^{-13}$

As we know that these two salts would both dissociate in the same way. So, we can say that as the Ksp value of AgBr has a smaller than CuBr then AgBr should precipitate first.

Now we have to calculate the concentration of bromide ion.

The solubility equilibrium reaction will be:

$CuBr\rightleftharpoons Cu^++Br^-$

The expression for solubility constant for this reaction will be,

$K_{sp}=[Cu^+][Br^-]$

$4.2\times 10^{-8}=0.073\times [Br^-]$

$[Br^-]=5.75\times 10^{-7}M$

Now we have to calculate the concentration of silver ion.

The solubility equilibrium reaction will be:

$AgBr\rightleftharpoons Ag^++Br^-$

The expression for solubility constant for this reaction will be,

$K_{sp}=[Ag^+][Br^-]$

$7.7\times 10^{-13}=[Ag^+]\times 5.75\times 10^{-7}M$

$[Ag^+]=1.34\times 10^{-6}M$

Now we have to calculate the percent of $Ag^+$ remains in solution at this point.

Percent of $Ag^+$ remains = $\frac{1.34\times 10^{-6}}{0.073}\times 100$

Percent of $Ag^+$ remains = 0.0018 %

3 0

2 years ago

When reactants and products are being formed at an equal rate in a chemical reaction, the ____. a. reaction is endergonic b. fre

attashe74 [19]

<h2>The answer is option b "free energy is zero"</h2>

Explanation

The reaction that has negative free energy are called exergonic reactions that means the reactants have more free energy than the product formed.
The reaction that has positive free energy are called endergonic reactions that means the final state or the products formed have more free energy than the initial state or the reactants.
The reaction that has zero free energy occurs when the free energy of both reactants and the products are same hence the rate of formation of products and reactants are equal.
Therefore, when reactants and products are being formed at an equal rate the free energy is zero.

3 0

3 years ago

Срочноооооооооооооо!!!!

Ymorist [56]

Answer:

I can't answer this as I am not able to read the Question

4 0

2 years ago

Help please !!!

castortr0y [4]

Kinetic energy is the correct answer for this question

4 0

2 years ago