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Rasek [7]
3 years ago
14

What element is being oxidized in the following redox reaction?

Chemistry
1 answer:
DIA [1.3K]3 years ago
8 0

Answer:

The element that has been oxidized is the N

Explanation:

Zn²⁺(aq) + NH₄⁺(aq) → Zn(s) + NO₃⁻(aq)

See all the oxidation states:

Zn²⁺  → acts with +2

In ammonia, H acts with +1 and N with -3

Zn(s), acts with 0. In all the elements in ground state, the oxidation state is 0.

Zn changed from 2+ to 0. The oxidation number, has decreased.

This element has been reduced.

NO₃⁻ (aq) it's a ion, from nitric acid.

N acts with +5

O acts with -2

The global charge is -1

The N, has increased the oxidation state, so this element is the one oxidized.

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The heat of vaporization ΔHv of dichloromethane CH2Cl2 is 28.0 /kJmol . Calculate the change in entropy ΔS when 3.3g of dichloro
ella [17]

Answer:

\Delta _VS=3.48x10^{-3}kJ=3.48J

Explanation:

Hello,

In this case, the change in the entropy, by knowing the change in the enthalpy and the temperature for a vaporization process is given by:

\Delta _VS=\frac{\Delta _VH}{T_V}

Thus, we start by computing the change in the enthalpy for the 3.3g of dichloromethane  as shown below:

\Delta _VH=3.3gCH_2Cl_2 *\frac{1molCH_2Cl_2}{84.9gCH_2Cl_2}*28\frac{kJ}{molCH_2Cl_2} =1.09kJ

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\Delta _VS=\frac{1.09kJ}{(39.8+273.15)K}\\\\\Delta _VS=3.48x10^{-3}kJ=3.48J

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In the reaction, Zn(s) + 2 HCl(aq) --> ZnCl2 (aq)+ H2(g), 25 grams of Zn are reacted with 17.5 g of HCl. How many grams of H2
Gennadij [26K]

Answer:

0.480 g of H₂ are produced, in the reaction.

Explanation:

This is the reaction:

Zn(s)  +  2HCl → ZnCl₂ (aq) +  H₂ (g)

We havethe mass of both reactants, so we must work with them to find out the limiting reactant and then, determine the amount of H₂ produced.

Let's convert the mass to moles ( mass / molar mass)

25 g / 65.41 g/mol = 0.382 moles Zn

17.5 g / 36.45 g/mol = 0.480 moles HCl

Ratio is 1:2, so 1 mol of Zn react with the double of moles of HCl.

0.382 moles of Zn would need the double of moles to react, so (0.382 .2) = 0.764 moles of HCl. → We only have 0.480 moles, so the acid is the limiting.

Now let's determine the moles of H₂ formed.

Ratio is 2:1, so If i take account the moles I have, I will produce the half of moles of my product.

0.480 moles / 2 = 0.240 moles of H₂ are produced.

To find out the mass, we must multiply mol . molar mass

0.240 mol . 2g/mol = 0.480 g

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3 years ago
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