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3 years ago

30.5 g of sodium metal reacts with a solution of excess lithium bromide. How many grams

Chemistry

1 answer:

vagabundo [1.1K]3 years ago

6 0

Answer:

9.28 g of Lithium metal

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

Na + LiBr —> NaBr + Li

Next, we shall determine the mass of sodium metal, Na that reacted and the mass of lithium metal, Li produced from the balanced equation.

Molar mass of Na = 23 g/mol

Mass of Na from the balanced equation = 1 x 23 = 23 g

Molar mass of Li = 7 g/mol

Mass of Li from the balanced equation = 1 x 7 = 7 g

Summary:

From the balanced equation above,

23 g of Na reacted to produce 7 g of Li.

Now, we can obtain the mass of lithium metal, Li produced by reacting 30.5 g of sodium metal, Na as shown:

From the balanced equation above,

23 g of Na reacted to produce 7 g of Li.

Therefore, 30.5 g of Na will react to produce = (30.5 x 7)/23 = 9.28 g of Li.

Therefore, 9.28 g of Lithium metal, Li were produced from the reaction.

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Gaseous ICl (0.20 mol) was added to a 2.0 L flask and allowed to decompose at a high temperature:

Ne4ueva [31]

Answer:

The Kc is 1.36 (but this is not an option, may be the options are wrong, or may be I was .. Thanks!)

Explanation:

Let's think all the situation.

2 ICl(g) ⇄ I₂(g) + Cl₂(g)

Initially 0.20 - -

Initially I have only 0.20 moles of reactant, and nothing of products. In the reaction, an x amount of compound has reacted.

React x x/2 x/2

Because the ratio is 2:1, in the reaction I have the half of moles.

So in equilibrium I will have

(0.20 - x) x/2 x/2

Notice that I have the concentration in equilibrium so:

0.20 - x = 0.060

x = 0.14

So in equilibrium I have formed 0.14/2 moles of I₂ and H₂ (0.07 moles)

Finally, we have to make, the expression for Kc and remember that must to be with concentration in M (mol/L).

As we have a volume of 2L, the values must be /2

Kc = ([I₂]/2 . [H₂]/2) / ([ICl]/2)²

Kc = (0.07/2 . 0.07/2) / (0.060/2)²

Kc = 1.225x10⁻³ / 9x10⁻⁴

Kc = 1.36

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2 years ago

What is an example of land features formed from constructive forces?

elena-14-01-66 [18.8K]

It’s C.valley formed from water erosion

7 0

2 years ago

When Xavier places his hands near a light bulb, he notices that certain areas around the light bulb are warmer than others. Whic

UNO [17]

The area directly above the light bulb is warmest because of convection.

3 0

3 years ago

Read 2 more answers

State the coefficient required to correctly balance the following chemical equation:

frez [133]

Answer:

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3 years ago

For the equation 2H₃PO₄ + 3Ca ⇒ 3H₂ + Ca₃(PO₄)₂ suppose you had 27.4 grams of H₃PO₄?

Darya [45]

Answer:

Explanation:

Given 2H₃PO₄ + 3Ca ⇒ 3H₂ + Ca₃(PO₄)₂

27.4g

=(27.4g/98g/mol)

= 0.280 mole H₃PO₄ used

Ca Used:

Rxn Ratio H₃PO₄ : Ca => 2:3

∴ moles Ca used = 3/2(0.280) mole Ca =0.420 mole Ca

grams Ca used = 0.420 mole Ca x 40 g/mole = 16.8 grams Ca used

Grams H₂ Produced:

Rxn Ratio H₃PO₄ : H₂ => 2:3 => moles H₂ produced = 3/2(0.28 mole H₂) = 0.420 mole H₂ = (0.420 mole H₂ x 2.02 g/mole) = 0.8484 grams H₂(g) Produced.

Moles Ca₃(PO₄)₂ Produced:

FWt Ca₃(PO₄)₂ = 310 g/mole

Rxn Ratio H₃PO₄ : Ca₃(PO₄)₂ => 2:1

∴moles Ca₃(PO₄)₂ Produced = 1/2(moles H₃PO₄ used)

= 1/2(0.28 mole) = 0.14 mole Ca₃(PO₄)₂

If you want grams Ca₃(PO₄)₂, multiply moles Ca₃(PO₄)₂ by formula weight.

3 0

3 years ago