Answer:
9.28 g of Lithium metal
Explanation:
We'll begin by writing the balanced equation for the reaction. This is given below:
Na + LiBr —> NaBr + Li
Next, we shall determine the mass of sodium metal, Na that reacted and the mass of lithium metal, Li produced from the balanced equation.
Molar mass of Na = 23 g/mol
Mass of Na from the balanced equation = 1 x 23 = 23 g
Molar mass of Li = 7 g/mol
Mass of Li from the balanced equation = 1 x 7 = 7 g
Summary:
From the balanced equation above,
23 g of Na reacted to produce 7 g of Li.
Now, we can obtain the mass of lithium metal, Li produced by reacting 30.5 g of sodium metal, Na as shown:
From the balanced equation above,
23 g of Na reacted to produce 7 g of Li.
Therefore, 30.5 g of Na will react to produce = (30.5 x 7)/23 = 9.28 g of Li.
Therefore, 9.28 g of Lithium metal, Li were produced from the reaction.
