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Kaylis [27]
2 years ago
10

>

Mathematics
2 answers:
amm18122 years ago
5 0

I'm not in highschool but I did the math I think it's 18

Anastaziya [24]2 years ago
3 0

Answer:

The Answer is D

Step-by-step explanation:

437-18.5=419.5

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What constant do you need to add to each quadratic to complete the square? 1. x2 - 4x = 0 4 2. x2 - 8x = 6 9 3. 3x2 + 18x = 24 1
Radda [10]
1) You must add 4 to each side to complete the square.
2) You must add 16 to each side to complete the square.
3) You must add 27 to each side to complete the square.

Explanation:
1) x²-4x=0
To find the number that we add to both sides, we look at b, the cofficient of x.  It is -4. We divide it by 2 and square it; -4/2 = -2; (-2)² = 4.  This is the value that we add to both sides.

2) x²-8x=6
-8/2 = -4; (-4)²=16
We add 16 to each side to complete the square.

3) 3x²+18x=24
First we can factor a 3 out of the left side:
3(x²+6x) = 24
Our b value is now 6.  6/2 = 3; 3²=9.  The 9 would, however, go in the parentheses, so it would be multiplied by 3, which makes 27; this means we would add 27 to both sides.
6 0
2 years ago
10.) For the natural logarithm function, determine the point on the curve where its associated tangent line passes through the
Lunna [17]

f(x)=lnx

y=f(x)

dy/dx= 1/x

tangent at (x,y) has slope 1/x

eqn of tangent is y = mx + c

since the tangent passes through origin, c=0

substitute y = lnx and m= 1/x to above eqn

lnx = 1

x=e

y=lne=1




4 0
2 years ago
Roman buys seed packets for the school garden. One packet of radish seeds costs $1.75. One packet of tomato seeds costs $2.50. L
HACTEHA [7]
Answer:

C. t=23,r=9 .

Step-by-step explanation:

Let r represent the cost of one packet of radish seeds and let t represent the cost of one packet of tomato seeds.

Roman spent $62.75

This implies that,

1.75r+2.5t=62.75...eqn1

Roman bought 32 packets of seeds and one packet of radish seeds costs
$ 1.75.
One packet of tomato seeds costs $ 2.50.

This implies that,

r+t=32...eqn2

Using guess and check means we substitute into the given equation.

A) We substitute t=8,r=24 into both equations.

1.75(8)+2.5(24)=62.75...eqn1

14+60\ne 62.75...eqn1

8+24=32...eqn2

Both equations are not satisfied.

B)

We substitute t=9,r=23 into both equations.

1.75(9)+2.5(23)=62.75...eqn1

15.75+57.5\ne 62.75...eqn1

9+23=32...eqn2

Both equations are not satisfied.

C)

We substitute t=23,r=9 into both equations.

1.75(23)+2.5(9)=62.75...eqn1

40.25+22.5 =62.75...eqn1

23+9=32...eqn2

Both equations are satisfied.

Hence the solution is,

t=23,r=9

D) We substitute t=24,r=8 into both equations.

1.75(24)+2.5(8)=62.75...eqn1

42+20\ne 62.75...eqn1

24+8=32...eqn2

Both equations are not satisfied.
4 0
3 years ago
Read 2 more answers
I need help with number 3 please and thank you
murzikaleks [220]
So here we're dealing with equivalent fractions.
It's really simple to find the answer, so I'll try to explain the best I can.

2 dogs / 5 cats is really just 2/5.
If we want to find an equivalent fraction, we have to multiply the numerator and the denominator by the same number.

Currently the number of cats is 5, and we need it to be 140. What we need to do is find the number it has to be multiplied by to equal 140, which is 140 divided by 5. 140 divided by 5 is 28, so 5 x 28 = 140!

We need to multiply the denominator (5) by 28, so that we can get 140. What we have now is ?/140.

Like I said, to find an equivalent fraction, we need to multiply the numerator by the same number as we did the denominator, which is 28!

2 x 28 = 56.

So 2/5 is the same as 56/140.

The answer is D) 56 Dogs/140 Cats.

Hope this helps!
If you're confused about anything leave me a reply and I'll try to explain the best that I can!
3 0
2 years ago
The glee club has 120 cupcakes to sell. they have decided to arrange the cupcakes in the shape of a rectangle such that the rows
DochEvi [55]
120 cupcakes
Even # rows
Odd # columns

12: 1, 2,3,4,6, 12 (integers?)

I see only one arrangement with odd column & even rows
3 columns, 40 rows
That's mainly because 120 is an even number.

5 0
2 years ago
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