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ahrayia [7]
3 years ago
8

The dimensions of a square are altered so that 8inches is added to one side while 3 inches is subtracted from the other. The are

a of the resulting rectangle is 126in^2 .What was the original side length of the square?
Mathematics
1 answer:
OlgaM077 [116]3 years ago
7 0
Let s original sides, l length, w width:

s+8=l

s-3=w

lw= 126in²

substitute:

(s+8)(s-3)=126

s²+5s-24=126

s²+5x-150=0

(s-10)(s+15)

s=10

each side is 10 inches


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