After 1st year: 250$:100%=x$:116%, 250$*116%=x$*100%, x=(250*116)/100=290$. After 1st year I will have 290$
After 2nd year: 290$:100%=x$:116%, x=(290*116)/100=336.4$. After 2nd year I will have 336.4$
After 3rd year I will have (336.4*116)/100=390.224$
After 4th yr: (390.224*116)/100=452.65984$
After 5th yr: (452.65984*116)/100=525.085$
After- 6th yr: 609.1$, 7th yr: 706.556$, 8th yr: 819.605$, 9th yr: 950.742$
10th yr: 1102.86$, 11th yr: 1279.32$, 12th yr: 1484.01$, 13th yr: 1721.45$,
14th yr: 1996.88$, 15th: 2316.38$, 16th yr: 2687$, 17th yr: 3116.92$
After 18 years I will have 3615.63$.
Answer:
The equation of the line is, y = x
Step-by-step explanation:
The constraints of the required linear equation are;
The point through which the line passes = (2, 2)
The line to which the required line is parallel = y = x + 4
Two lines are parallel if they have the same slope, therefore, we have;
The slope of the line, y = x + 4 is m = 1
Therefore, the slope of the required line = 1
The equation of the required lime in point and slope form becomes;
y - 2 = 1 × (x - 2)
∴ y = x - 2 + 2 = x
The equation of the required line is therefore, y = x
(2(-2)+9(5)-5)-(6(-2)-4(5)+2)
(-4+45-5)-(-12-20+2)
(45-9)-(-32+2)
36+30
66
Answer:
Step-by-step explanation:
18.796
Answer:
564cvbfgrg
Step-by-step explanation:
