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kondor19780726 [428]
3 years ago
14

Particles 1 and 2 each mass m fixed to the ends of a rigid massless rod of length L1 + l2 with L1 = 20cm and l2 = 80 cm. The rod

is held horizontally on the fulcrum and then released. What are the magnitudes of the initial accelerations of particles 1 and 2.
Physics
1 answer:
Degger [83]3 years ago
7 0

Answer:

Sorry bro I don't even know the answer

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A person is walking briskly in a straight line. The figure shows a graph of the person’s position x as a function of time t. Wha
Nina [5.8K]

The average velocity over the interval 6\le t\le 10 is

\dfrac{x(10)-x(6)}{10\,\mathrm s-6\,\mathrm s}=\dfrac{6\,\mathrm m-2.67\,\mathrm m}{4\,\mathrm s}=0.8325\,\dfrac{\mathrm m}{\mathrm s}

where x(t) is the person's position at time t. I've taken the liberty of estimating x(6)\approx2.67\,\mathrm m. The closest choice among the answers is 0.8\,\dfrac{\mathrm m}{\mathrm s}.

7 0
2 years ago
Which of the following statements are true?
yawa3891 [41]
A. False, because the SI unit for frequency is Hertz, 1 hertz equals 1 wave passing a fixed point in 1 second,

B. True, f and Nu (v)

C. To find the frequency of a wave, divide velocity of wave by wavelength

D. False, the period of a wave is measured in frequency (Hertz)
8 0
3 years ago
As plants and animals decay, they release carbon dioxide. When CO2 dissolves in water, it creates carbonic acid. *
Juliette [100K]

Answer:

A limestone plateau has no surface water. All the water is pulled underground through cracks and crevices in the surface. What most likely will cause the underground of the plateau to change over time?

Physical weathering due to frost wedging

Physical weathering due to abrasion

Chemical weathering due to oxygen

Chemical weathering due to water  Correct Answer

Explanation:

8 0
2 years ago
A green block of mass m slides to the right on a frictionless floor and collides elastically with a red block of mass M which is
EastWind [94]

Answer:

m=M

Explanation:

In case we say that the green block's mass m is less than red block's mass M, then the green block would have bounced and moved back to the left instead of coming to rest. The other case where if mass of green block's mass m would have been greater than the red block's mass M, the green block would have kept moving to the right instead of coming to rest. After collision, the red block moves to the right because of exchange of velocities. Therefore, m=M since m comes to rest and M moves to the right

4 0
3 years ago
String 1 is pulled on with a force of 50 N to the right. String 1 is attached to a mass of 20 kg on a level surface. String 2 co
vladimir1956 [14]

The masses are pulled in only one dimension, so we can ignore the forces acting in the vertical direction. We take the positive direction to be to the right.

For the 20 kg mass, the net force is

∑ <em>F</em>₁ = 50 N - <em>T</em>

where <em>T</em> is the tension in string 2.

For the 40 kg mass, the net force is

∑ <em>F</em>₂ = <em>T</em>

For both masses combined, the net force is

∑ <em>F</em> = 50 N

Use Newton's second law to compute the acceleration of the system:

50 N = (20 kg + 40 kg) <em>a</em>

<em>a</em> = (50 N) / (60 kg) ≈ 0.83 m/s²

Then use the net force equation for the 40 kg mass to compute the tension:

<em>T</em> = (40 kg) <em>a</em> ≈ 33 N

7 0
3 years ago
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