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kondor19780726 [428]
3 years ago
14

Particles 1 and 2 each mass m fixed to the ends of a rigid massless rod of length L1 + l2 with L1 = 20cm and l2 = 80 cm. The rod

is held horizontally on the fulcrum and then released. What are the magnitudes of the initial accelerations of particles 1 and 2.
Physics
1 answer:
Degger [83]3 years ago
7 0

Answer:

Sorry bro I don't even know the answer

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The magnitudes of the charge densities on the inner and outer shells are now changed (keeping λinner = -λouter) so that the resu
elena-14-01-66 [18.8K]

Answer: a) Cnew=Cinitial ; b) λouter new=  2*λ outer initial

Explanation: In order to explain this question we have to take into account the expression of teh cylinder capacitor given by:

C/L= (2*π*εo)/ln (b/a)=  where b and a are the outer and inner radius, respectively. L is the length of the capacitor.

As you can se this formule depents  of geometrical characateristics  of the capacitor.

The capacitance is the same after change the densities of charge.

On the other hand,

The new charge in each cylinder ( inner and outer) is determined

The new potential is 2 times the initial one so

V new= 2* Vinitial

Also we know that

Vnew= Q/C= λnew*L/C;   C= constant

using this formule and considering  that V new is doubled then the charge per one meter length,  is also doubled .

This is as follow:

Vnew=  λnew*L/C=  

λnew =  (2*Vinitial)* C/L= 2  (λ initial)

Then  λouter new = 2* λouter initial

5 0
3 years ago
Suppose 1 kg of Hydrogen is converted into Helium. a) What is the mass of the He produced? b) How much energy is released in thi
morpeh [17]

Answer:

a) m = 993 g

b) E = 6.50 × 10¹⁴ J

Explanation:

atomic mass of hydrogen = 1.00794

4 hydrogen atom will make a helium atom = 4 × 1.00794 = 4.03176

we know atomic mass of helium = 4.002602

difference in the atomic mass of helium = 4.03176-4.002602 = 0.029158

fraction of mass lost = \dfrac{0.029158}{4.03176}= 0.00723

loss of mass for 1000 g = 1000 × 0.00723 = 7.23

a) mass of helium produced = 1000-7.23 = 993 g (approx.)

b) energy released in the process

E = m c²

E = 0.00723 × (3× 10⁸)²

E = 6.50 × 10¹⁴ J

4 0
3 years ago
Read 2 more answers
Calcula el peso aparente de una bola de aluminio de 50 cm3, cuando se encuentra totalmente sumergida en alcohol. Datos: la densi
artcher [175]

Answer:

W_apparent = 93.1 kg

Explanation:

The apparent weight of a body is the weight due to the gravitational attraction minus the thrust due to the fluid where it will be found.

            W_apparent = W - B

The push is given by the expression of Archimeas

            B = ρ_fluide g V

            ρ_al = m / V

            m = ρ_al V

we substitute

            W_apparent = ρ_al V g - ρ_fluide g V

            W_apparent = g V (ρ_al - ρ_fluide)

       

we calculate

           W_apparent = 980 50 (2.7 - 0.8)

           W_apparent = 93100 g

            W_apparent = 93.1 kg

7 0
3 years ago
A man starts from rest and accelerates at 4.00 m/s2. If he covers a distance of 525 m, how long does he accelerate?
rosijanka [135]

Answer:

16.2 s

Explanation:

Given:

Δx = 525 m

v₀ = 0 m/s

a = 4.00 m/s²

Find: t

Δx = v₀ t + ½ at²

525 m = (0 m/s) t + ½ (4.00 m/s²) t²

t = 16.2 s

5 0
3 years ago
Which step should you take before you begin a scientific investigation? Print the directions after you complete the experiment.
agasfer [191]

Answer:

Clarify any confusing information in the instructions.

Purchase the equipment and chemicals you will need.

Explanation:

Steps of a scientific investigation include identifying a research question or problem, forming a hypothesis, gathering evidence, analyzing evidence, deciding whether the evidence supports the hypothesis, drawing conclusions, and communicating the results.

8 0
3 years ago
Read 2 more answers
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