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kondor19780726 [428]
3 years ago
14

Particles 1 and 2 each mass m fixed to the ends of a rigid massless rod of length L1 + l2 with L1 = 20cm and l2 = 80 cm. The rod

is held horizontally on the fulcrum and then released. What are the magnitudes of the initial accelerations of particles 1 and 2.
Physics
1 answer:
Degger [83]3 years ago
7 0

Answer:

Sorry bro I don't even know the answer

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The robot HooRU is lost in space, floating around aimlessly, and radiates heat into the depths of the cosmos at the rate of 13.1
ahrayia [7]

Answer:

The temperature is  T  = 168.44 \ K

Explanation:

From the question ewe are told that

   The rate of heat transferred is    P  = 13.1 \ W

     The surface area is  A = 1.55 \ m^2

      The emissivity of its surface is  e = 0.287

Generally, the rate of heat transfer is mathematically represented as

           H  =  A e \sigma  T^{4}

=>         T  =  \sqrt[4]{\frac{P}{e* \sigma } }

where  \sigma is the Boltzmann constant with value  \sigma  = 5.67*10^{-8} \ W\cdot  m^{-2} \cdot  K^{-4}.

substituting value  

             T  =  \sqrt[4]{\frac{13.1}{ 0.287* 5.67 *10^{-8} } }

            T  = 168.44 \ K

7 0
3 years ago
Quartz has an index of refraction of 1.46. Diamond has in index of refraction of 2.42. In which material does a light ray enteri
Ksivusya [100]
<span>Diamond slowdown light more than Quartz , because diamonds have a greater index of refraction. Light will bend when its move from one medium to another. The Index of Refraction of Material is found by comparing the speed of light in their respective mediums.</span>
4 0
3 years ago
Read 2 more answers
Inside a NASA test vehicle, a 3.50-kg ball is pulled along by a horizontal ideal spring fixed to a friction-free table. The forc
erastova [34]
F(of spring)=230x=ma=3.5(5)=17.5=230x; x=0.07m.
3 0
3 years ago
An electromagnetic wave has a frequency of 4.0 x 1018 Hz. What is the
trapecia [35]

Answer: D

Wavelength λ = 7.5 × 10^-11 m

Explanation:

You are given the frequency of an electromagnetic wave to be:

F = 4.0 x 1018 Hz. And the speed of light C to be

C = 3 × 10^8 m/s

From wave speed formula:

Wave speed is the product of waves frequency and wavelength. That is,

V = fλ

Where

f = frequency

λ = wavelength

V = C = speed of light

Substitute the values of the parameters into the formula

C = fλ

3 × 10^8 = 4 × 10^18 × λ

Make λ the subject of formula

λ = (3×10^8)/(4×10^18)

λ = 7.5 × 10^-11 m

Therefore, the wavelength of the wave is 7.5 × 10^-11 m

8 0
3 years ago
Computers A and B implement the same ISA. Computer A has a clock cycle time of 200 ps and an effective CPI of 1.5 for some progr
lesya692 [45]

Answer:

Computer A is 1.41 times faster than the Computer B

Explanation:

Assume that number of instruction in the program is 1

Clock time  of computer A is CT_{A} =200 ps

Clock time  of computer B is CT_{B} =250 ps

Effective CPI of computer A is CPI_{A} =1.5

Effective CPI of computer B isCPI_{B} =1.7

CPU time of A is

CPU_{time}=instructions \times CPA_{A} \times CT_{A}\\CPU_{time}=1 \times 1.5 \times 200=300 sec

CPU time of B is

CPU_{time}=instructions \times CPA_{B} \times CT_{B}\\CPU_{time}=1 \times 1.7 \times 250=425 sec

Hence Computer A is Faster by \frac{425}{300} =1.41

Computer A is 1.41 times faster than the Computer B

4 0
3 years ago
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