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3 years ago

EXPERTS/ACE and people that wanna help 4 sure only!

Physics

1 answer:

oee [108]3 years ago

7 0

To do this you want to solve for one variable at a time. So we want to cancel out a variable. Lets cancel x. I will multiply the first equation by the number 4 to get 4y=4x-16.
Now lets solve equation 2 for y, giving
-3y=-4x+3 now add equation 1 to equation 2
Y =-13
Now plug that back in to either
-13=x-4
X=-9
So the answer is (-9,-13)

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A student reads that soil is formed in part due to the weathering of rocks. The student lists methods in which rocks break down

Fittoniya [83]

The answer is 1,2,3 and 4

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3 years ago

A concert loudspeaker suspended high off the ground emits 32.0 W of sound power. A small microphone with a 1.00 cm^2 area is 52.

lesya [120]

Answer:

Sound Intensity at microphone's position is $9.417\times 10^{- 4} W/m^{2}$

The amount of energy impinging on the microphone is $9.417\times 10^{- 8} W/m^{2}$

Solution:

As per the question:

Emitted Sound Power, $P_{E} = 32.0 W$

Area of the microphone, $A_{m} = 1.00 cm^{2} = 1.00\times 10^{- 4} m^{2}$

Distance of microphone from the speaker, d = 52.0 m

Now, the intensity of sound, $I_{s}$ at a distance away from the souce of sound follows law of inverse square and is given as:

$I_{s} = \frac{P_{E}}{Area} = \frac{P_{E}}{4\pi d^{2}}$

$I_{s} = \frac{32.0}{4\pi (52.0)^{2}} = 9.417\times 10^{- 4} W/m^{2}$

Now, the amount of sound energy impinging on the microphone is calculated as:

If $I_{s}$ be the Incident Energy/ $m^{2}/s$

Then

The amount of energy incident per 1.00 $cm^{2} = 1.00\times 10^{- 4} m^{2}$ is:

$I_{s}(1.00\times 10^{- 4}) = 9.417\times 10^{- 4}\times 1.00\times 10^{- 4} = 9.417\times 10^{- 8} J$

7 0

3 years ago

The intensity of light from a star (its brightness) is the power it outputs divided by the surface area over which it’s spread:

kow [346]

Answer:

$\frac{d_{1}}{d_{2}}=0.36$

Explanation:

1. We can find the temperature of each star using the Wien's Law. This law is given by:

$\lambda_{max}=\frac{b}{T}=\frac{2.9x10^{-3}[mK]}{T[K]}$ (1)

So, the temperature of the first and the second star will be:

$T_{1}=3866.7 K$

$T_{2}=6444.4 K$

Now the relation between the absolute luminosity and apparent brightness is given:

$L=l\cdot 4\pi r^{2}$ (2)

Where:

L is the absolute luminosity
l is the apparent brightness
r is the distance from us in light years

Now, we know that two stars have the same apparent brightness, in other words l₁ = l₂

If we use the equation (2) we have:

$\frac{L_{1}}{4\pi r_{1}^2}=\frac{L_{2}}{4\pi r_{2}^2}$

So the relative distance between both stars will be:

$\left(\frac{d_{1}}{d_{2}}\right)^{2}=\frac{L_{1}}{L_{2}}$ (3)

The Boltzmann Law says, $L=A\sigma T^{4}$ (4)

σ is the Boltzmann constant
A is the area
T is the temperature
L is the absolute luminosity

Let's put (4) in (3) for each star.

$\left(\frac{d_{1}}{d_{2}}\right)^{2}=\frac{A_{1}\sigma T_{1}^{4}}{A_{2}\sigma T_{2}^{4}}$

As we know both stars have the same size we can canceled out the areas.

$\left(\frac{d_{1}}{d_{2}}\right)^{2}=\frac{T_{1}^{4}}{T_{2}^{4}}$

$\frac{d_{1}}{d_{2}}=\sqrt{\frac{T_{1}^{4}}{T_{2}^{4}}}$

$\frac{d_{1}}{d_{2}}=0.36$

I hope it helps!

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3 years ago

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ludmilkaskok [199]

Answer:

Option C=> π+.

Explanation:

Just as it is given in the question above, we can see that the addition or combination of proton and neutron gives what is known as QUARKS.

Quarks are not easily measured because one can not see and study a quark independently; quarks move in multiples together.

The study of Quarks is very important in physics because they relate very well with electromagnetic force, strong force, weak force and Gravitational force.

"...When the remaining quarks combine to form a single particle, it is a π+".

π+ is a meson or a pion and it contains quarks and anti-quarks too

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3 years ago

A beach ball is rolling in a straight line toward you at a speed of .5 meters per second. It's momentum is .25 kgxm/sec what is

stepladder [879]

Its 15 pounds (ilb) i think

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