All categories

3 years ago

If you measure a change in temperature, then the _____.

Physics

1 answer:

kherson [118]3 years ago

6 0

Answer:

C. total heat energy of the substance has increased

Explanation:

This is because when there is a change in temperature, the heat energy of a substance either increases or decreases. If the temperature increases, its heat energy increases and if its temperature decreases, its heat enery decreases.

You might be interested in

A stack of 55 business cards is 1.85 cm tall. Use this information to determine the thickness of one business

Sindrei [870]

To find the answer, take 55 and divide it by 1.85 to get the thickness of one card. In this case the answer would be 29.72973 cm. each.

8 0

3 years ago

Read 2 more answers

A joule is an amount of energy, and a watt is a rate of using energy, defined as 1 W = 1 J / s. How many joules of energy are re

Naily [24]

How many joules of energy are required to run a 100 W light bulb for one day?

A100 joulesB100W × 24hr joulesC100W × 24hr × 60min∕hr joulesD100W × 24hr × 60min∕hr × 60s∕min joules

4 0

2 years ago

The gage pressure in a liquid at a depth of 3 m is read to be 39 kPa. Determine the gage pressure in the same liquid at a depth

ioda

Answer: 117 kPa

Explanation:

For the liquid at depth 3 m, the gauge pressure is equal to = P₁=39 kPa

For the liquid at depth 9m, the gauge pressure is equal to= P₂

Now we are given the condition that the liquid is same. That must imply that the density must be same throughout the depth.

So, For finding gauge pressure we have formula P= ρ * g * h

Also gravity also remains same for both liquids

So taking ratio of their respective pressures we have

$\frac{P_{1} }{\\P_2}$ = $\frac{density * g * h_1}{density * g * h_2}$

So $\frac{39}{P_2}$ = $\frac{3}{9}$

Or P₂= 39 * 3 = 117 kPa

5 0

3 years ago

Driving a motor vehicle often requires __________ reaction time.

Anastasy [175]

It often requires STANDARD reaction time

8 0

2 years ago

Read 2 more answers

At a certain instant, the earth, the moon, and a stationary 1160 kg spacecraft lie at the vertices of an equilateral triangle wh

Afina-wow [57]

Answer:

$W = 1.22 \times 10^9 J$

Explanation:

Initial potential energy of the given spacecraft is given as

$U = -\frac{GM_e m}{r} - \frac{GM_m m}{r}$

so we have

$U = - \frac{Gm}{r}(M_e + M_m)$

so we have

$M_e = 5.98 \times 10^{24} kg$

$M_m = 7.35 \times 10^{22} kg$

$m = 1160 kg$

$r = 3.84 \times 10^8 m$

$U = - \frac{(6.67 \times 10^{-11})(1160)}{3.84 \times 10^8}(5.98 \times 10^{24} + 7.35 \times 10^{22})$

$U = -1.22 \times 10^9 J$

now total work done to move it to infinite is given

W = 0 - U

$W = 1.22 \times 10^9 J$

6 0

2 years ago