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Ugo [173]
3 years ago
12

If an object is to rest on an incline without slipping, then friction must equal the component of the weight of the object paral

lel to the incline. This requires greater and greater friction for steeper slopes. Show that the maximum angle of an incline above the horizontal for which an object will not slide down is θ.
Physics
1 answer:
leonid [27]3 years ago
3 0

Answer:

\theta = tan^{-1}\mu

Explanation:

As we know that if the object is placed on the inclined plane then the force of friction on the object is counterbalanced by the component of the weight of the object along the inclined plane.

So we can say

F_f = mgsin\theta

now if we increase the inclination of the plane then the component of the weight weight along the inclined plane will increase and hence the friction force will also increase.

As we know that the limiting value or the maximum value of friction force at the static condition is given by

F_f = \mu N

N = mg cos\theta

so we have

F_f = \mu (mg cos\theta)

so we will have

mg sin\theta = \mu (mg cos\theta)

so now we have

tan\theta = \mu

so maximum possible angle of the inclined plane is

\theta = tan^{-1}\mu

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Answer:

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3 years ago
When the starter motor on a car is engaged, there is a 290 A current in the wires between the battery and the motor. Suppose the
Tema [17]

Answer:

33.6\times10^{-4}}\text{ m} = 3.36 mm

Explanation:

From Ohm's law,

V = IR (Voltage = Current * Resistance)

R = \dfrac{V}{I}

The geometric definition of resistance is

R = \rho\dfrac{l}{A}

where \rho is the resistivity of the material, l  and A are the length and cross-sectional area, respectively.

A = \rho\dfrac{l}{R}

A = \rho\dfrac{l\timesI}{V}

Since the wire is assumed to have a circular cross-section, its area is given by

A = \pi\dfrac{d^2}{4} where d is the diameter.

\pi\dfrac{d^2}{4} = \rho\dfrac{l\timesI}{V}

d = \sqrt{\dfrac{4\rho l I}{\pi\times V}}

Resistivity of copper = 1.68\times10^{-8}. With these and other given values,

d = \sqrt{\dfrac{4\times1.68\times10^{-8}\times1.5\times290}{3.14\times 0.55}}

d = \sqrt{1128.43\times10^{-8}}

d = 33.6\times10^{-4} \text{ m}

5 0
3 years ago
1. What are the two quantities involved when calculating MOMENTUM?
Snezhnost [94]

Answer:

Mass and Velocity

Explanation:

Momentum = Mass  X Velocity

or p=m' x v

since in physics p is quantity momentum and m stands for mass and v stands for velocity.

Hope this helps :)

8 0
3 years ago
A motorist travels a distance of 406 km during a 7 hr period. What was the average speed in (a) km/hr and (b) m/sec?
Sholpan [36]
The motorist travels (a) 58 km/h and (b) ~16.1 m/sec
4 0
3 years ago
Read 2 more answers
6. The momentum of a 30.0 g bird with a speed of 12 m.s-1 is 0.36 kg.m.s-1. What will be its momentum 12s later if a constant .0
Keith_Richards [23]

Answer:

Explanation:

initial momentum = .36 kg.m.s⁻¹

negative impulse = force x time = .02 x 12 = .24 kg.m.s⁻¹

final momentum - initial momentum = impulse

final momentum = initial momentum + impulse

= .36 - .24

= .12 kg.m.s⁻¹

7 0
3 years ago
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