The time interval needed for the disk to rev from leave to 25.0 m/s
= 0.57 s
<h3>What is the time interval?</h3>
- A larger period of time can be split up into multiple shorter, equal-length segments.
- These are referred to as time periods. Consider the scenario where you wished to gauge a car's speed over an hour-long trip. You could break up an hour into ten-minute segments.
- In Hz, frequency is defined as the number of cycles per second. Simply divide 1 by the frequency to determine the time interval for a known frequency (e.g., a frequency of 100 Hz has a time interval of 1/(100 Hz) = 0.01 seconds; 500 Hz has a time interval of 1/(500Hz) = 0.002 seconds, etc.).
Given:
vo = 0
v = 25.4 m/s
r = 0.95 m
n = 1.21 rev
A.
r*ω = v
ω = v/r
= 25.4/.95
= 26.74 rad/s
B.
θ = 2πn
= 2π × (1.21)
= 7.6 m
Using equation of motion,
ωf^2 = ωi^2 + 2αθ
(26.74)^2 = 2 × α × (7.6)
α = 715.03/15.2
= 47.04 rad/s^2
C.
Using equation of motion,
θ = ωi*t + 1/2*α*t^2
θ = 0 + 1/2*α*t^2
7.6 = 47.04/2 × t^2
= sqrt(0.323)
= 0.57 s
Therefore the correct answer is 0.57 s
To learn more about time interval, refer to:
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Answer:
The induced current will flow in a direction north of the plane of the paper
Explanation:
This is in compliance with faraday's right hand rule pictured below.
Answer:
<h2>0.5J</h2>
Explanation:
given data
Force applied F= 1N
extension e= 0.1m
let us find the spring constant first
applying
F=ke
k=F/e
k=1/0.1
k=10N/m
Step two:
Required is the work done
we know that the expression/formula for the work done by a spring is given as
Wd=1/2kx^2
x=0.4m
substitute
Wd= 1/2*10*0.4^2
Wd=0.5*10*0.16
Wd=0.5J
Answer: 15.6 metres
Explanation:
Given that:
length of wave (λ)= ?
Frequency of wave F = 28 Hertz
Speed of wave (V) = 437 m/s
The wavelength is the distance covered by the wave in one complete cycle. It is measured in metres, and represented by the symbol λ.
So, apply V = F λ
Make λ the subject formula
λ = V / F
λ = 437 m/s / 28 Hertz
λ = 15.6 m
Thus, the length of the wave is 15.6 metres
Answer:
x = 7.62 m
Explanation:
First we need to calculate the weight of the rocket:
W = mg
we will use the gravity as 9.8 m/s². We have the mass (500 g or 0.5 kg) so the weight is:
W = 0.5 * 9.8 = 4.9 N
We know that the rocket exerts a force of 8 N. And from that force, we also know that the Weight is exerting a force of 4.9. From here, we can calculate the acceleration of the rocket:
F - W = m*a
a = F - W/m
Solving for a:
a = (8 - 4.9) / 0.5
a = 6.2 m/s²
As the rocket is accelerating in an upward direction, we can calculate the distance it reached, assuming that the innitial speed of the rocket is 0. so, using the following expression we will calculate the time which the rocket took to blast off:
y = vo*t + 1/2 at²
y = 1/2at²
Solving for t:
t = √2y/a
t = √2 * 20 / 6.2
t = √6.45 = 2.54 s
Now that we have the time, we can calculate the horizontal distance:
x = V*t
Solving for x:
x = 3 * 2.54 = 7.62 m
