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nata0808 [166]
4 years ago
10

A wave with a speed of 437 m/s has a frequency of 28 hertz. What is the length of the wave?

Physics
1 answer:
Natasha2012 [34]4 years ago
6 0

Answer: 15.6 metres

Explanation:

Given that:

length of wave (λ)= ?

Frequency of wave F = 28 Hertz

Speed of wave (V) = 437 m/s

The wavelength is the distance covered by the wave in one complete cycle. It is measured in metres, and represented by the symbol λ.

So, apply V = F λ

Make λ the subject formula

λ = V / F

λ = 437 m/s / 28 Hertz

λ = 15.6 m

Thus, the length of the wave is 15.6 metres

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AfilCa [17]

Answer:

  • Potential Energy = mgl (1 - cosθ)

Explanation:

<h3>Given :-</h3>
  • Mass of stick = m
  • Length of stick = l
  • Angle = θ

<h3>To Find :-</h3>
  • Increase potential energy

<h3>Solution :-</h3>

✪ <u>According to the given </u><u>data</u> :-

 ⠀⠀⠀→ cosθ = ᵇ/ₕ

 ⠀⠀⠀→ cosθ = ᴬᴮ/l

 ⠀⠀⠀→ AB = l cosθ

❂ <u>For </u><u>Height</u> :-

 ⠀⠀⠀→ h = l - l cosθ

 ⠀⠀⠀→ h = l (1-cosθ)

☯ <u>As we know that</u>

 ⠀⠀⠀→ Potential Energy = mgh

 ⠀⠀⠀→ Potential Energy = mg × l (1-cosθ)

 ⠀⠀⠀→ Potential Energy = mgl (1-cosθ)

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3 years ago
What kind of fluctuations in weather patterns do you expect to see in your area? Will the fluctuations or changes vary by month,
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A rolling ball has 18 joules of kinetic energy and is rolling 3 m/s find its mass
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4 years ago
What is the mathematical relationship between wavelength and energy transmission?.
WITCHER [35]

The mathematical relationship between wavelength and energy transmission E = hv.

<h3>What is Wavelength and Energy transmission?</h3>

A waveform signal that is carried in space or down a wire has a wavelength, which is the separation between two identical places (adjacent crests) in the consecutive cycles. This length is often defined in wireless systems in metres (m), centimetres (cm), or millimetres (mm) (mm). The wavelength is most frequently described in nanometers (nm), which are units of 10⁻⁹ m, or angstroms (Å), which are units of 10⁻¹⁰ m, for infrared (IR), visible light (UV), and gamma radiation (γ).

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6 0
2 years ago
Using Hooke's law, F spring=k delta x, find the distance a spring with an elastic constant of 4 N/cm will stretch if a 2 newton
pishuonlain [190]

Hello!

Using Hooke's law, F spring=k delta x, find the distance a spring with an elastic constant of 4 N/cm will stretch if a 2 newton force is applied to it.

Data:

Hooke represented mathematically his theory with the equation:

F = K * Δx  

On what:

F (elastic force) = 2 N

K (elastic constant) = 4 N/cm

Δx (deformation or elongation of the elastic medium or distance from a spring) = ?

Solving:


F = K * \Delta{x}

2\:N = 4\:N/cm*\Delta{x}

4\:N/cm*\Delta{x} = 2\:N

\Delta{x} = \dfrac{2\:\diagup\!\!\!\!\!N}{4\:\diagup\!\!\!\!\!N/cm}

simplify by 2

\Delta{x} = \dfrac{2}{4}\frac{\div2}{\div2}

\boxed{\boxed{\Delta{x} = \dfrac{1}{2}\:cm}}\Longleftarrow(distance)\end{array}}\qquad\checkmark

Answer:

B.) 1/2 cm

_______________________

I Hope this helps, greetings ... Dexteright02! =)

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