**Answer:**

6.77 m/s

**Explanation:**

First, in the x direction:

Given:

Δx = 3.17 m

v₀ = v cos 30.8° = 0.859 v

a = 0 m/s²

Δx = v₀ t + ½ at²

(3.17 m) = (0.859 v) t + ½ (0 m/s²) t²

3.17 = 0.859 v t

3.69 = v t

Next, in the y direction:

Given:

Δy = 0.432 m

v₀ = v sin 30.8° = 0.512 v

a = -9.81 m/s²

Δy = v₀ t + ½ at²

(0.432 m) = (0.512 v) t + ½ (-9.81 m/s²) t²

0.432 = 0.512 v t − 4.905 t²

Two equations, two variables. Solve for t in the first equation and substitute into the second equation:

t = 3.69 / v

0.432 = 0.512 v (3.69 / v) − 4.905 (3.69 / v)²

0.432 = 1.89 − 66.8 / v²

66.8 / v² = 1.458

v² = 45.8

v = 6.77

<h2>Answer: Fluids
</h2>

<u>**Convective heat transfer occurs only in fluids**</u>, through the movement of groups of molecules that make up the medium.

Being this molecular movement, related to the properties of the fluid that change with temperature.

This means that convection occurs when **the hottest parts of a fluid ascend to the coldest zones**, generating a continuous circulation of the fluid (better known as <u>convective current</u>) **transmitting heat to the cold zones by decreasing the density caused by the increase in temperature.**

**Answer:**

they play hide and seek with me and im always the seeker U-U

**Explanation:**

Answer:

The height of the rock, measured relative to the cliff top, at its highest point = 18.68 m

The height of the rock, measured relative to the ground, at its highest point = 30.84 m

Explanation:

The rock is thrown with an initial velocity, u = 8.2 m/s.

a = - 1.62 m/s² (negative sign because the rock is moving upwards against the planet's gravity)

At the maximum height reached, velocity, v = 0 m/s

y = maximum height reached, measured from the top of the cliff.

Using the equations of the motion

v² = u² + 2ay

0 = 8.2² + 2(-1.8)y

- 3.6y = - 67.24

y = 18.68 m

So the maximum height reached by the rock, measured from the ground = 18.68 + 12.16 = 30.84 m