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zmey [24]
3 years ago
6

A rectangular flat coil moves at constant speed through a uniform magnetic field. The direction of the field is into the plane o

f the paper. What is the direction of the the induced current in the coil as it moves from P to Q?

Physics
1 answer:
alukav5142 [94]3 years ago
3 0

Answer:

The induced current will flow in a direction north of the plane of the paper

Explanation:

This is in compliance with faraday's right hand rule pictured below.

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in a certain experiment, a radio transmitter emits sinusoidal electromagnetic waves of frequency 105.0 mhz in opposite direction
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As a result, the hollow is 10.90 meters long and the distance between the nodal planes is 1.36 meters.

<h3>Explain electromagnetic waves.</h3>

The oscillations between an electric field and a magnetic field produce waves known as electromagnetic waves, or EM waves.

By definition, we understand that the frequency equals,

f = c/λ

where,

λ = wavelength

c= Speed of light

λ = 2L / n

While the wavelength is equal to,

Where,

L = Length

n = Number of antinodes/nodes

PART A) We know that the first component's wavelength is 110 MHz, so

λ = c/ f

λ = 3*10^8 / 11*10^6

λ = 1.36m

Therefore the distance between the nodal planes is 1.36m

PART B) For this part we need to find the Length through the number of nodes (8) and the wavelength, that is,

λ` = 2l /n

L = 8*2.72/ 2

L = 10.90m

Therefore the length of the cavity is 10.90m.

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7 0
1 year ago
The student concluded that the current in the LDR is inversely proportional to the potential difference across the LDR. Explain
Andrej [43]

Answer:

The graph shows direct proportion  because it is a straight line

through the origin.

Explanation:

7 0
4 years ago
a rocket engine can accelerate a rocket launched from rest vertically up with an acceleration of 22.9 m/s2. however, after 50.0
xxTIMURxx [149]

The acceleration of a rocket engine is given here, and after 50 seconds of flight, the engine fails, and we must determine the altitude of the rocket at the time the engine fails.  Because the rocket starts from rest, the time taken is 50 seconds, the initial velocity is zero, and the acceleration is 22.9 meters per second square. So we use the kinamatics equation s equal to v. I t plus half 8 square. There is no acceleration at the start. 22.9 and t is 50 seconds, so displacement 2.86 times 10 to the power 4 is met. This is the rocket's displacement in 50 seconds, so this is the rocket's altitude when the engine fails.

<h3>What exactly is accelerate?</h3>
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Hence, There is no acceleration at the start. 22. This is the rocket's displacement in 50 seconds, so this is the rocket's altitude when the engine fails.

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3 0
1 year ago
Two identical space probes are orbiting Jupiter. Scientists determine that one of the space probes has a larger gravitational fo
galina1969 [7]

If the probes are identical, then the one that feels a larger gravitational
force is orbiting closer to Jupiter than the other one is.

If they're not identical, then the one with greater mass will feel more
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the same distance from Jupiter.  (We know this from the experimental
observation that fatter people weigh more, even on Earth.)
6 0
3 years ago
Read 2 more answers
An aerobatic airplane pilot experiences weightlessness as she passes over the top of a loop the loop maneuver. The acceleration
Natali5045456 [20]

The radius of the loop is 18.9 km

Explanation:

When the airplane is at the top of the loop, the pilot experiences two forces:

  • The force of gravity, acting downward, of magnitude mg
  • The normal reaction exerted by the seat on the pilot, also acting  downward, N

Since the plane is moving in a circular motion, the net force on the pilot must be equal to the centripetal force, therefore we can write:

mg+N = m\frac{v^2}{r}

where

m is the mass of the pilot

g=9.8 m/s^2 is the acceleration of gravity

N is the normal reaction

v = 430 m/s is the speed of the plane

r is the radius of the loop

Here we are told that the pilot feel weightless at the top of the loop: this means that the normal reaction is zero,

N = 0

Therefore the equation becomes

mg=\frac{mv^2}{r}

And so we can find the radius of the loop:

r=\frac{v^2}{g}=\frac{430^2}{9.8}=18.9 \cdot 10^3 m = 18.9 km

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8 0
3 years ago
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