Answer:
Step-by-step explanation:
First confirm that x = 1 is one of the zeros.
f(1) = 2(1)^3 - 14(1)^2 + 38(1) - 26
f(1) = 2 - 14 + 38 - 26
f(1) = -12 + 38 = + 26
f(1) = 26 - 26
f(1) = 0
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next perform a long division
x -1 || 2x^3 - 14x^2 + 38x - 26 || 2x^2 - 12x + 26
2x^3 - 2x^2
===========
-12x^2 + 28x
-12x^2 +12x
==========
26x -26
26x - 26
========
0
Now you can factor 2x^2 - 12x + 26
2(x^2 - 6x + 13)
The discriminate of the quadratic is negative. (36 - 4*1*13) = - 16
So you are going to get a complex result.
x = -(-6) +/- sqrt(-16)
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2
x = 3 +/- 2i
f(x) = 2*(x - 1)*(x - 3 + 2i)*(x - 3 - 2i)
The zeros are
1
3 +/- 2i
Answer:
I think the answer is 7;
Step-by-step explanation:
All i did was subtract Q11 from all 4 of its sides;
11=4=7
Answer:
30
Step-by-step explanation:
5+5+5+5+5+5 =
30
Answer:
the top one (-40)8 is the correct answer
I think it’s 3 sets of carnations, so that’d be 18 singular carnation flowers
it might not be right, but i was able to get 3 sets for each of the 3 types of flowers
so there’d be 18 carnation flowers, 6 sunflowers, and 12 tulips
so the answer is 18 carnations