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4 years ago

Is -15 greater than 5?

Mathematics

2 answers:

snow_tiger [21]4 years ago

4 0

No, it’s a negative so no. it is before the 0 on a number line and the five is after which mean -15 is smaller

ozzi4 years ago

4 0

Answer:

Step-by-step explanation:

-15 < 5

{-15, -14, ..., -1, 0, 1, ..., 4, 5}

-15 is lower on the number line than 5 so, it is less than 5.

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What is the median of the menu items in the plot below?

DerKrebs [107]

Step-by-step explanation:

There are 13 numbers here:

30, 30, 31, 32, 42, 49, 58, 58, 67, 67, 69, 78, 90.

The median number is the 7th number, which is 58.

6 0

4 years ago

Read 2 more answers

Can someone find The volume of the shaded portion of the cylinder??????????????????????? I have attached the picture

Yakvenalex [24]

Step-by-step explanation:

Area of circle = πr², π = 22/7 or 355/133. Here it is said to use '3.14'. I will use the same.

Volume = cross-section area * height

Cross-section area of bigger one = π(3m)²

Volume = π(3m)² * height

= 9π * 5 m³ = 45π m³

Cross-section area of smaller one= π(1m)²

Volume = π(1m)² * height

= π * 5 m³ = 5π m³

Since a large part(cylinder of 1 m is not here):

Required volume = total volume - volume of smaller circle(cylinder)

= 45π - 5π m³

= 40π m³ = 40(3.14) m³

= 125.6 m³

4 0

3 years ago

If the circle has the same diameter as the edge length of the square, then the area of this circle is ___________the area of the

WINSTONCH [101]

Answer:

The area of this circle is $(\frac{\pi}{2} )$ the area of the square.

For the uniform electric field normal to the surface, the flux through the surface is electric field multiplied by the area of this surface.

Therefore, Φsquare is $(\frac{2}{\pi} )$ ϕcircle

Step-by-step explanation:

Area of the circle is given by;

$A_c = \frac{\pi d^2}{4}$

Area of the square is given by;

$A_s = L^2$

relationship between the edge length of the square, d, and length of its side, L,

$d = \sqrt{L^2 + L^2} \\\\d = \sqrt{2L^2}$

But area of the square , $A_s = L^2$

$d = \sqrt{2A_s}$

Then, the area of the square in terms of the edge length is given by;

$A_s = \frac{d^2}{2}$

Area of the circle in terms of area of the square is given by;

$A_c = \frac{\pi d^2}{4} = \frac{\pi}{2}(\frac{d^2}{2} )\\\\But \ A_s = \frac{d^2}{2} \\\\A_c = \frac{\pi}{2}(\frac{d^2}{2} )\\\\A_c = \frac{\pi}{2}(A_s )$

For the uniform electric field normal to the surface, the flux through the surface is electric field multiplied by the area of this surface.

Ф = E.A

Flux through the surface of the circle is given by;

$\phi _{circle} = E.(\frac{\pi d^2}{4})$

Flux through the surface of the square is given by;

$\phi _{square} = E.(\frac{d^2}{2} )\\\\\phi _{square} =E.(\frac{d^2}{2} ).(\frac{\pi}{2} ).(\frac{2}{\pi} )\\\\\phi _{square} =E.(\frac{\pi d^2}{4} ).(\frac{2}{\pi} )\\\\\phi _{square} =(\phi _{circle}).(\frac{2}{\pi} )$