1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
alex41 [277]
4 years ago
8

2) How do you calculate

Chemistry
1 answer:
Mice21 [21]4 years ago
7 0

Answer:

<em>If two(or more) forces act on an object in the same direction, the net force is the sum of the forces. In the diagram at left, the net force is 30 Newtons to the right</em>

You might be interested in
Suppose you need 0.12L of a 0.13M solution of NiCl2, but all you have is a solution that is a solution that is 0.23M. What volum
topjm [15]

- 0.05 L needs to be added to the original 0.12 L solution in order to dilute it from 0.13 M to 0.23 M.

The dilution problem uses the equation :

M_aV_a= M_bV_b

The initial molarity (concentration) M_a = 0.13 M

The initial volume V_a = 0.12 L

The desired molarity (concentration) M_b = 0.23 M

The volume of the desired solution V_b = ( 0.12 + x L )

Substituting values in above equation;

(0.13 M ) (0.12 L) = (0.23 M ) (0.12 L + x L)

0.0156 M L = 0.0276 M L + 0.23 x M L

- 0.012 M L = 0.23 x M L

x = - 0.05

Therefore, - 0.05 L needs to be added to the original 0.12 L solution in order to dilute it from 0.13 M to 0.23 M.

Learn more about molarity here:

brainly.com/question/26873446

#SPJ4

3 0
2 years ago
Suppose that you add 24.3 g of an unknown molecular compound to 0.250 kg of benzene, which has a K f of 5.12 oC/m. With the adde
pochemuha

Solution :

We know that :

$\Delta T_f = k_f.m$  and   $m=\frac{w_2}{m_2 \times w_1}$

Then, $\Delta T_f = k_f.\frac{w_2}{m_2.w_1}$   ..................(1)

Where,

w_1 = amount of solvent (in kg)

w_2 = amount of solute (in kg)

m_2 = molar mass of solute (g/mole)

m = molality of solution (mole/kg)

Given :

\Delta T_f = 3.14\ ^\circ C,   k_f= 5.12\ ^\circ C/m

                              =5.12 \ ^\circ C/mole/kg

                              =5.12 \ ^\circ C \ kg/mole

w_1 = 0.250 kg,  w_2 = 24.3 g

Then putting this values in the equation is (1),

$3.14 = \frac{5.12 \times 24.3}{m_2 \times 0.250}$

$m_2 = \frac{5.12 \times 24.3}{3.14 \times 0.250}$

m_2= 158.49  g/mole

So, the molar mass of the unknown compound is 158.49 g/mole.

7 0
3 years ago
Which of the following correctly compares the redii of Fond F?
Eva8 [605]

Answer:easy

Explanation: ok so the answer is +;<:.";:[]{=+because 7'.]-=

'.

.[]'..;;'[p

7 0
3 years ago
Suppose 0.410 kg of hexane are burned in air at a pressure of exactly 1 atm and a temperature of 13.0 °C. Calculate the volume o
3241004551 [841]

Answer:

The answer is 671 litres of carbon dioxide is produced from 0.410 kg of hexane

Explanation:

We first write a balanced reaction for the complete combustion of hexane thus

The stoichiometry of the cumbustion of hexane in air is

2C6H14(g)+18O2(g)→12CO2(g)+14H2O(l) or

C6H14(g)+9O2(g)→6CO2(g)+7H2O(l)

From the above reaction it is observed that one mole of hexane burns completely in the presence of oxygen to produce 6 moles of carbon dioxide

Therefore we calculate the nuber of moles of hexane present in the sample thus

Mass hexane of sample = 0.41 kg

Molar nass of hexane = 86.18 g/mol

number of moles of hexane = (mass of hexane)/(molar mass of hexane) = (0.41×1000)/86.16 = 410/86.16 = 4.76 moles

As we have seen from the chemical reaction, 1 mole of H6H14 produces 6 moles of CO2 hence 4.76 moles of Hexane produces

4.76×6 moles of CO2 which is 28.55 moles of CO2

From the question we have the temperature and the pressure of the production of CO2 as

Temperature of reaction = 13° C converting to kelving gives= 13+273.15 = 286.15 K

and pressure = 1 atmosphere or 101325 Pa

13.0∘C=13.0∘C+273.15=286.15 K

The volume of the produced CO2 can be calculated using the combined ideal gas equation given by

P×V=n×R×T where

Here

P = Gas pressure (of CO2 )

V = Volume (of the CO2)

n = number of moles of gas (CO2) present

R = universal gas constant, equal to 0.0821 atm× L/(mol× K )

T = absolute temperature in Kelvin

Thus we have

1×V = 28.55×0.0821×286.15  or V  = 670.76L

Rounding up the answer to 3 significant digits we have

670.76L ≅ 671L

671 litres of carbon dioxide is produced from 0.410 kg of hexane

8 0
4 years ago
Compare similarities and differences between the Plum Pudding Model, Nuclear Model and Bohr Model (6 marks)
Svetlanka [38]

Answer:

The three models describes the structure of an atom based on different views.

Explanation:

Plum pudding model described the atom of consisting of negatively charged electrons embedded in positively charged substrates; this was later proven to be false. The Bohr's model described the electrons in an atom to orbit round the nucleus at different energy, the closer it's to the nucleus, the lesser the energy it needs. The Rutherford model claims the the nucleus of the atom contains protons and neutrons which forms the mass of the atom, the electrons surrounds the nucleus and it forms the volume of the atom.

4 0
4 years ago
Other questions:
  • Mass is a property of matter true or false
    12·2 answers
  • How many moles of glucose (C6H12O6) are in 5.0 liters of a 2.5 M C6H12O6 solution?
    15·1 answer
  • A 6.59-gram sample of a compound is dissolved in 250. grams of benzene. The freezing point of this solution is 1.02°C below that
    6·1 answer
  • If a mixture of gases contained 78% nitrogen at a pressure of 984 torr and 22% carbon dioxide at 345 torr, what is the total pre
    9·1 answer
  • : Which of the following is produced during the formation of photochemical smog ? ...
    7·1 answer
  • Which if the following questions can be answered by science?​
    11·1 answer
  • List four energy resources​
    14·2 answers
  • What is a hot spot? Must be in your own words ( please hurry)
    13·2 answers
  • D. Period 3 element with 6 valence electrons
    9·1 answer
  • Concentration required to begin precipitate pbcl2 for pbcl2 ksp=1. 17×10−5
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!